matrix manupulation and reading diagonally

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NIKHIL
NIKHIL am 8 Dez. 2020
Kommentiert: NIKHIL am 11 Dez. 2020
Hello Team,
i have a matrix
Matrix_test = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16];
I want to read the matrix in the order mentioned in the matrix.
Starting from left bottom (1), then right top (2) and then again 2nd diagonal from left (3,4) and then 2nd right diagonal (5,6) and so on and so forth.
Please support in resolving it.
Edit : i there any way to create this kind of matrix for any n-by-n matrix automatically. i have created this Matrix_test manually but if i want 8x8 matrix in similar pattern . How to create it through generic code.
Thanks in advance.

Akzeptierte Antwort

Stephan
Stephan am 8 Dez. 2020
This function may help:
M = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16]
MyResult = readDiag(M)
function R = readDiag(M)
R = cell(2,numel(diag(M)));
for k = 1:numel(diag(M))-1
R{1,k} = diag(M,-numel(diag(M))+k);
R{2,k} = diag(M,numel(diag(M))-k);
end
R = reshape(R,[],1);
R = [R; {diag(M)}];
R = cell2mat(R);
end
result is:
M =
13 10 5 2
7 14 11 6
3 8 15 12
1 4 9 16
MyResult =
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
  2 Kommentare
NIKHIL
NIKHIL am 11 Dez. 2020
Thank your for your solution.
NIKHIL
NIKHIL am 11 Dez. 2020
Hello Stephen, I have edited one additional question related to this query. How to create similar type of Matrix_test automatically with some code. can you please revert back to this query also ?

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Weitere Antworten (1)

Bruno Luong
Bruno Luong am 8 Dez. 2020
Bearbeitet: Bruno Luong am 8 Dez. 2020
Matrix_test = [13,10,5,2;7,14,11,6;3,8,15,12;1,4,9,16]
[m,n]=size(Matrix_test);
[i,j]=ndgrid(1:m,1:n);
jmi = j(:)-i(:);
[~,is]=sortrows([-abs(jmi) jmi]);
Matrix_test(is)
  4 Kommentare
Bruno Luong
Bruno Luong am 11 Dez. 2020
Create matrix with dimension m x n.
m=8; n=8;
[i,j]=ndgrid(1:m,1:n);
jmi = j(:)-i(:);
[~,is]=sortrows([-abs(jmi) jmi]);
M=zeros(m,n);
M(is)=1:m*n
NIKHIL
NIKHIL am 11 Dez. 2020
Thank you so much Bruno for quick response.
It is working really good

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