How can I remove successive repeated numbers (column wise) from a matrix?

For example If I have a matrix like this

A = [11 35 57 45 94;
     26 45 69 45 86;
     58 45 39 96 35;
     87 59 64 56 45]

The output should be a column vector (i have just showed transpose of it)

[11 26 58 87 35 45 59 57 69 39 64 45 96 56 94 86 35 45]'

I have tried to use unique() function but, the output it gives is

[11 26 58 87 35 45 59 57 69 39 64 96 56 94 86]'

Answer 1

[Ameer Hamza]

Easy peasy

A = [11 35 57 45 94;
     26 45 69 45 86;
     58 45 39 96 35;
     87 59 64 56 45]
B = A(:);

or

B = reshape(A, [], 1)

[Viswanath V]

No, I want to remove the successive repeated values from the input A (in this case its 45). But according to your code it will just reshape the matrix into a column vector.

[Ameer Hamza]

In that case try this

idx = [diff(A(:))~=0; true];
B = A(idx);

[Viswanath V]

No, thats not the required output.

[Ameer Hamza]

It is same as you mentioned in the question

A = [11 35 57 45 94;
     26 45 69 45 86;
     58 45 39 96 35;
     87 59 64 56 45];
B_required = [11 26 58 87 35 45 59 57 69 39 64 45 96 56 94 86 35 45]';
idx = [diff(A(:))~=0; true];
B = A(idx);

is_same = isequal(B, B_required)

Result

is_same
is_same =
  logical
   1

[Viswanath V]

Oh, I am extremely sorry! I had made a mstake in my code.

Thank you very much.

[Ameer Hamza]

I am glad to be of help!