Define a name of the variable using the value of other variable

1 Ansicht (letzte 30 Tage)
Suppise I have data
Month Day Visitors
----------------------------
January 1 100
January 7 50
February 1 400
February 3 200
I want to create a variable that is a proxy for months such as
Month Day Visitors proxy_January proxy_February
------------------------------------------------
January 1 100 1 0
January 7 50 1 0
February 1 400 0 1
February 3 200 0 1
One way to do this is to define variables one by one for each month.
But I would like to know how I can let Matlab do this automatically.
I start with
set_of_month=unique(T.Month)
that will give me the set of months. Then I can iterate over the set of months.
But how can I define a variable using set_of_months? I like to do something like
for i=1:length(set_of_states)
for j=1:height(T)
if T.Month(j)=set_of_month(i)
T.set_of_month(i)=1
else
T.set_of_month(i)=0
end
end
end
Please advise.

Akzeptierte Antwort

Marco Riani
Marco Riani am 5 Dez. 2020
Please let me know if I understood correctly your question.
Month={'January'; 'January'; 'February'; 'February'};
set_of_month=unique(Month);
% Add a matrix of zeros to host the dummy variables
dum=zeros(length(Month),length(set_of_month));
T=[table(Month) array2table(dum)];
% Add the labels
T.Properties.VariableNames(2:end)=set_of_month;
% Add the ones in the corresponding position
for i=1:length(set_of_month)
for j=1:height(T)
if strcmp(T.Month{j},set_of_month{i})
T{j,i+1}=1;
end
end
end
disp(T)
% Month February January
% ____________ ________ _______
%
% {'January' } 0 1
% {'January' } 0 1
% {'February'} 1 0
% {'February'} 1 0
  3 Kommentare
alpedhuez
alpedhuez am 5 Dez. 2020
"You cannot assign numeric values to a datetime array."

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Weitere Antworten (2)

Walter Roberson
Walter Roberson am 5 Dez. 2020
T.(set_of_month{i}) = value
  4 Kommentare
Walter Roberson
Walter Roberson am 5 Dez. 2020
The implication is that set_of_month is not a cell array of character vectors as you had claimed.
Perhaps your month entries in the table are individual cells rather than character vectors. If so then
monthname = set_of_month{i}{1};
T.(monthname) = value
and monthname is something that you can strcmp() or ismember()

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Steven Lord
Steven Lord am 5 Dez. 2020
Bearbeitet: Steven Lord am 5 Dez. 2020
M = repelem(["January"; "February"], 2, 1);
D = [1; 7; 1; 3];
V = [100; 50; 400; 200];
T = table(M, D, V, 'VariableNames', ["Month", "Day", "Visitors"])
T = 4x3 table
Month Day Visitors __________ ___ ________ "January" 1 100 "January" 7 50 "February" 1 400 "February" 3 200
UM = unique(T.Month);
for whichMonth = 1:numel(UM)
T.("proxy_" + UM(whichMonth)) = T.Month == UM(whichMonth);
end
T
T = 4x5 table
Month Day Visitors proxy_February proxy_January __________ ___ ________ ______________ _____________ "January" 1 100 false true "January" 7 50 false true "February" 1 400 true false "February" 3 200 true false
Alternately the unstack function may do what you want (or something similar to what you want.)

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