Copy of one field of a structured array
6 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Is there a way to make a copy of one field of a structured array without doing a loop? I have tried but it just results in the first element.
Creation of sample structure
for i=1:5
A(i).A = i;
A(i).B = i+10;
end
>>C = A.B
C =
11
Likewise
>> C = A(1:3).B
C =
11
instead of C(1).B = 11, C(2).B = 12, and C(3).B = 13 like I want.
0 Kommentare
Akzeptierte Antwort
per isakson
am 12 Mär. 2013
Bearbeitet: per isakson
am 12 Mär. 2013
One way to do it:
>> C = cell2struct( num2cell([A.B]), {'B'} )
C =
5x1 struct array with fields:
B
>> C(1).B
ans =
11
>> C(2).B
ans =
12
another
>> C = struct( 'B', num2cell([A.B]) )
C =
1x5 struct array with fields:
B
>> C(1).B
ans =
11
>> C(2).B
ans =
12
>>
Weitere Antworten (2)
the cyclist
am 12 Mär. 2013
Bearbeitet: the cyclist
am 12 Mär. 2013
Yet another way:
[C(1:numel(A)).B] = A.B;
Note that this method will not overwrite other fields of C, if they exist. Some of the methods in other answers will, so be cautious!
2 Kommentare
per isakson
am 12 Mär. 2013
Bearbeitet: per isakson
am 12 Mär. 2013
The two functions, struct and cell2struct, create a new struct and overwrite an existing C.
I'll try to remember that numel(A) in the rhs-expression creates a new struct if C does not exist. And I'll reread the entry on deal in the documentation.
Siehe auch
Kategorien
Mehr zu Structures finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!