How to make a loop until the same result is obtained

Hello,

I need help how to be used correctly in the loop, I have here a parameter table.

Example: I have k that place in the equation so i get d=23.83 and cheak if that no same ,continue until is same Out=d.

Thanks for the helpers

for k=[2.73 2.56 2.47 2.42 2.39]
    d=130-(K*(350/9));
    if d/130==[0.1 0.18 0.23 0.26 0.28]
       Out=d
    end
    end

[KSSV]

d/130==[0.1 0.18 0.23 0.26 0.28]

The above line is not correct...

[Emilia]

Can please help me how it works

[KSSV]

d/130==[0.1 0.18 0.23 0.26 0.28]

The above will give you logical indices...The exact question what you asked is not clear.

[Emilia]

I meant that d/130==23.83/130=0.18 no same 0.10

d/130==30.44/130=0.23 no same 0.18

.

.

.

Until it's the same

d/130==37.06/130=0.28 same 0.28

Out=d

Hope this is clear :)

[KSSV]

for k=[2.73 2.56 2.47 2.42 2.39]
  d=130-(k*(350/9)) ;
  d/130
  if any(d/130==[0.1 0.18 0.23 0.26 0.28])
    Out=d
  end
end

ans = 0.1833

ans = 0.2342

ans = 0.2611

ans = 0.2761

ans = 0.2850

The values are close to two decimals...what to you want?

[Emilia]

yes that's what I meant.

To make that compare d/130 to [0.1 0.18 0.23 0.26 0.28] until have similar number.

Example the result 0.2850=0.28 ( two decimals) is same to 0.28 so i want that output will Out=d=37.06

[Rik]

So essentially you want to round to 2 decimals? Or do you have a variable number of digits you want to round to? And do you actually want to round the values, or just display them with 2 digits?

[Emilia]

yes to round the values so

ans = 0.1833=0.18 compare to 0.1

ans = 0.2342=0.23 compare to 0.18

ans = 0.2611=0.26 compare to 0.23

ans = 0.2761=0.27 compare to 0.26

ans = 0.2850=0.28 compare to 0.28 => same number => Out=d=37.06

Answer 1

[Doris Brand]

Would that do it?

Out = 0;
for k=[2.73 2.56 2.47 2.42 2.39]
  d=round((130-(k*350/9))/130,2);
  if ismember(d, [0.1 0.18 0.23 0.26 0.28])
    Out=d;
  end
end
fprintf('Out=d=%3.2f\n',Out)

[Emilia]

Thank you!