how to use "fullfile" with exportgrahics
4 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
alpedhuez
am 26 Nov. 2020
Kommentiert: alpedhuez
am 26 Nov. 2020
One can use fullfile for saveas
saveas(gcf, fullfile(directory, fileName),'jpeg')
But when I try to use
exportgraphics(gcf, fullfile(directory, fileName)', 'eps', 'Resolution',3000)
Then I get an error message
Input must be a row vector of characters or string scalar
What is the next step?
0 Kommentare
Akzeptierte Antwort
Ameer Hamza
am 26 Nov. 2020
Bearbeitet: Ameer Hamza
am 26 Nov. 2020
exportgraphics(gcf, fullfile(directory, fileName)', 'eps', 'Resolution',3000)
%^ remove it
Why did you put transpose operator? Also, the output of exportgraphics() depends on extension of filename. It didn't accept file type seperately. So the correct syntax is
fileName = 'filename.eps'
exportgraphics(gcf, fullfile(directory, fileName), 'Resolution', 3000)
Note that it is better to export the eps file as vector.
fileName = 'filename.eps'
exportgraphics(gcf, fullfile(directory, fileName), 'ContentType', 'vector')
2 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Printing and Saving finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!