How to calculate the value of the vector A in equation AXA' = b?

If I have

A*X*A' = b;

where:

A is a (1x2) unknown vector whose elements must be integers

A' is the transpose of A,

X is a (2x2) diagonal matrix (given)

b is a given scaler value.

How can I calculate the value of vector A?

Answer 1

[KSSV]

syms x  y 
A = [x  y] ;
X = rand(2) ; 
b = rand ; 
eqn1 = A*X*X'- b ==0
s = solve(eqn1,x,y) ;
x = double(s.x) 
y = double(s.y) 

[Adi Nor]

I receive an error: Unrecognized function or variable 'sx'.

[KSSV]

don't know why but mathworks link is behaving wierd......it is

x = double(s.x)     
y = double(s.y)  

[Adi Nor]

If I want the obtained values of A to be integers, what should I do?

[KSSV]

It depends on what your X, b values are. If you want them to be integers, use round.

[KSSV]

Hey please check the answer properly.....and see does it fit your requirement?