Why am I not able to plot the error vs iterations?

33 Ansichten (letzte 30 Tage)
Ipshita
Ipshita am 21 Nov. 2020
Kommentiert: Leo Torres am 3 Dez. 2020
I am new to MATLAB. Can someone please tell what should I do to get a plot of the error (here, abs (z-Z)) vs the number of iterations? Another question is, earlier I used different variables and for x-axis plot of i (using plot(i,abs(z-Z)), I used ilim([0 20]), which showed "undefined function ilim for input argument double". Does this mean I can plot only when variables are named as x and y?
z=1;
for i=1:100
f=(1-z)*exp(-2*z)-3*exp(-z)+2;
fprime=exp(-2*z)*(2*z-3)+3*exp(-z);
Z=z;
z=Z-f/fprime;
if abs (Z-z)<10^(-6)
break
end
x=i;
y=abs (Z-z);
plot(x,y)
xlim([0 20])
ylim([0 1])
end
  1 Kommentar
Serhiy Shtovba
Serhiy Shtovba am 21 Nov. 2020
  1. Type "hold on" before plot.
  2. But your code is not perfect. It is not a good idea to use plot inside for. It will be better to collect error on each iteration in vector, for example, y(i)=abs (Z-z), and finnaly, after end_of_for make your graph: plot(1:100, y, 'ro--'

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Image Analyst
Image Analyst am 21 Nov. 2020
You plotted inside the loop but did not put "hold on" so each time you plotted it blew away the prior data point. It's probably better to just keep track of the error and plot everything all at once once the loop exists:
z = 1;
for k = 1 : 100
f = (1-z)*exp(-2*z)-3*exp(-z)+2;
fprime = exp(-2*z)*(2*z-3)+3*exp(-z);
Z = z;
z = Z - f / fprime;
theError(k) = abs(Z - z);
if abs (Z-z)<10^(-6)
break
end
end
iterationNumber = 1 : length(theError);
plot(iterationNumber, theError, 'b.-', 'LineWidth', 2, 'MarkerSize', 30)
grid on;
xlim([1, max(iterationNumber)])
title('Error vs. Iteration Number', 'FontSize', 20);
xlabel('Iteration Number', 'FontSize', 20);
ylabel('abs(Error)', 'FontSize', 20);
Or else you'd have to say "hold on" inside the loop but then you'd only get markers and no lines connecting the markers.
z = 1;
for k = 1 : 100
f = (1-z)*exp(-2*z)-3*exp(-z)+2;
fprime = exp(-2*z)*(2*z-3)+3*exp(-z);
Z = z;
z = Z - f / fprime;
theError = abs(Z - z);
plot(k, theError, 'b.-', 'LineWidth', 2, 'MarkerSize', 30)
hold on;
if abs (Z-z)<10^(-6)
break
end
end
grid on;
title('Error vs. Iteration Number', 'FontSize', 20);
xlabel('Iteration Number', 'FontSize', 20);
ylabel('abs(Error)', 'FontSize', 20);
  3 Kommentare
Ipshita
Ipshita am 22 Nov. 2020
Thankyou very much for explaining so nicely and for fast response. I understood now :)
Leo Torres
Leo Torres am 3 Dez. 2020
Thanks for this clear answer. I was having a 'brain fart' plotting the relative error norm within a for loop and this helped greatly. Cheers! Saludos!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Setsuna Yuuki.
Setsuna Yuuki. am 21 Nov. 2020
You can store the data of (Z-z) in a vector:
for ...
zz(i) = (Z-z)
if abs(zz)<10^(-6)
break
end
end...
And leave the graph out of the loop
x=1:100;
y=zz;
plot(x,y);
xlim([0 20])
ylim([0 1])

Kategorien

Mehr zu Data Distribution Plots finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by