Antworten (2)

David Hill
David Hill am 19 Nov. 2020
Bearbeitet: David Hill am 19 Nov. 2020

0 Stimmen

[i,j]=meshgrid(1:100,1:200);
TheOne=reshape(sum((Png1(:,i)-Png2(:,j)).^2),100,[]);

4 Kommentare

Master Blabla
Master Blabla am 19 Nov. 2020
Could You get a little simple solution?
David Hill
David Hill am 19 Nov. 2020
Does not get any simpler.
Master Blabla
Master Blabla am 19 Nov. 2020
It does not work correctly
David Hill
David Hill am 19 Nov. 2020
Made a mistake. Try this.
[i,j]=meshgrid(1:100,1:200);
TheOne=reshape(sum((Png1(:,i)-Png2(:,j)).^2),200,[])';

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CHENG QIAN LAI
CHENG QIAN LAI am 24 Nov. 2020

0 Stimmen

[i,j]=ndgrid(1:100,1:200);
% 1 2 3 . . . 200
%---------------------------
% i= 1 1 1 . . . 1 | 1
% 2 2 2 . . . 2 | 2
% 3 3 3 . . . 3 | 3
% . . . | .
% . . . | .
% . . . | .
% 100 100 100 . . . 100 | 100
%---------------------------
% j= 1 2 3 . . . 200 | 1
% 1 2 3 . . . 200 | 2
% 1 2 3 . . . 200 | 3
% . . . | .
% . . . | .
% . . . | .
% 1 2 3 . . . 200 | 100
TheOne = i+j;

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Gefragt:

am 19 Nov. 2020

Beantwortet:

am 24 Nov. 2020

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