How do I use function for a function which has a matrix with variable index?

function[PacksA,PacksB,ContA,ContB,AR,BR,fA,fB]=OutAR_NotOutBR(i,Max,AR,BR,fB,fA,ContB)                   
if AR<Max  
  %PacksB, PacksA, ContB, ContA are vectors that vary according to the operation 
    PacksB=3; fB=fB+1;                                               
    PacksA=2; ContA(AR+1)=i; AR=AR+1;                                 
    if BR==1 
        PacksB(ContB(1))=4;   fB=fB+1;                                    
        ContB(1)=0; BR=BR-1; 
    elseif BR>=2 
  
       PacksB(ContB(1,1:2))=4;  fB=fB+2;                                    
        if BR==2 
            ContB=0; 
        else
            ContB(1)=ContB(3); ContB(1,2:3)=0;                    
        end
        BR=BR-2;                                                    
    end    
elseif AR==Max                                                                         
    PacksA=3;  fA=fA+1;                                                 
    PacksB=3;  fB=fB+1;
    if BR>0 
        PacksB(ContB)=4;   fB=fB+BR;       
    ContB=0; 
    BR=0;
end
%Hi. What's up? Is there someone here who can help me with this error?

%Error in ==> OutAR_NotOutBR at 2 %if AR<Max  

[Geoff Hayes]

Fidele - what can you tell us about the input parameters? What is AR and what is Max? Is the problem the missing end for your last if statement?

    if BR>0 
        PacksB(ContB)=4;   fB=fB+BR;   
    end % <--- should this be here?
    ContB=0; 
    BR=0;
    

[Fidele Adanvo]

AR is a value for exemple AR=1;

Max is the maximum value of AR and BR for exemple Max=3;

i,fB,fA are also values

ContB is vector.

if BR>0

PacksB(ContB)=4; fB=fB+BR;

end % <--- should this be here?

ContB=0;

BR=0;

This code is not all correct because when BR == 3

PacksB (ContB (1,3)) = ~ 4

ContB (1) ~ = 0

and BR=1

[Geoff Hayes]

You may need to use the MATLAB debugger to step through the code to get an idea of what is going wrong. I'm also not clear on your comment:

This code is not all correct because when BR == 3

PacksB (ContB (1,3)) = ~ 4

ContB (1) ~ = 0

and BR=1

Why?

[Fidele Adanvo]

I will make the code simpler. Let's assume I have this code. And depending on the input value I want to show assign a=10 and b=5 different values (disregard the value of the output C) or assign c=100 a value and disregard a and b.

function [a,b,c] = trial_function(num)

if num==2

a=10;

b=5

else if num==4

c=100;

end

%I am getting an error. Output argument "b" (and maybe others) not assigned during call to

%Please, can you help me.Thank you.

Answer 1

[Geoff Hayes]

Fidele - since your function signature is

 function [a,b,c] = trial_function(num)

then you need to assign values to each of the three output variables which you are not currently doing

if num==2
    a=10;
    b=5 
elseif num==4  % <---- note this should be elseif rather than else if
    c=100;
end

The easiest solution is to just assign default values to these three variables as

a = 0;
b = 0;
c = 0;
if num==2
    a=10;
    b=5 
elseif num==4  % <---- note this should be elseif rather than else if
    c=100;
end

But is the above code really what you want? Do you want to assign different values to a and b and c if num is 2 or 4 or any other integer?