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How to solve coupled partial differential equation with an integral term?

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I want to solve the below given PDE system in MATLAB,
I have written a code but I am not able to solve integro differential equation in this system.
%% discretizing a
dx=0.25;
x=0:dx:20;
m=length(x);
% discretizing time
dt=0.01;
%Tp=(10)^(-1);
% Tf=input('enter the max time');
Tf=20;
t=0:dt:Tf;
n=length(t);
%% parameter values
a3=0; a4=1000; rho = 0.2;
c=1; alpha = 0.40; mu = 0.30; k=0.5; lambda=50;
%% size of the matrix
A=zeros(m,n);
B=zeros(m,n);
S=zeros(1,n);
R=zeros(1,n);
sum=zeros(1,n);
%% initial data
S(1) = a4; % S_s
R(1) = a3; % R_s
%% defining functions
for i=1:m
a1(i) = 0; %l_s(a)
a2(i) = 0; %i_s(a)
p(i) = 1700*(1-exp(-x(i))); %p(a)
% p(i) = i; %p(a)
delta1(i) = 0.01; % delta_l(a)
delta2(i) = 0.4; % delta_i(a)
end
%% initial conditions
for i=1:m
A(i,1) = a1(i);
B(i,1) = a2(i);
sum(1)=trapz(p(i).* B(i,1))*dx;
end
% %trapz(p(i)* B(:,i))*dx%
%% discretizing age and time derivative
for j=1:n-1
for i=2:m-1
A(i,j+1)=A(i,j)+dt*(-(A(i+1,j) - A(i-1,j))/(2*dx) - alpha*A(i,j)-delta1(i)*A(i,j));
B(i,j+1)=B(i,j)+dt*(-(B(i+1,j) - B(i-1,j))/(2*dx) +alpha*A(i,j)-delta2(i)*B(i,j));
sum(j+1)=trapz(p(i).* B(i,j))*dx;
S(j+1) = S(j) + dt*(lambda - k*R(j).*S(j) - mu*S(j));
R(j+1) = R(j)+ dt*sum(j+1) - dt*c*R(j);
end
% boundary conditions
A(1,j+1)= rho*k*R(j)*S(j);
B(1,j+1)= (1-rho)*k*R(j)*S(j);
end
plot(t,S,'b-', t,R,'r-');
I have plotted the solution but the plot of R(t) is not correct, I feel that I am not able to solve integro differential correctly. Please help me to solve integro differential equation by some method.
  4 Kommentare
Bill Greene
Bill Greene am 16 Nov. 2020
I am confused by your boundary condition on l. You show
but it looks like in your code
Please clarify this.
MANOJ KUMAR
MANOJ KUMAR am 16 Nov. 2020
Sorry again this was a typo, I corrected it.

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Hewa selman
Hewa selman am 23 Dez. 2021
hello it does not work. could you please write the last version of your code again
with regards

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