About Choosing MATRIX element
6 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
function[Ybus] = ybus(zdata) %first function
nl=zdata(:,1); nr=zdata(:,2); R=zdata(:,3); X=zdata(:,4);
nbr=length(zdata(:,1)); nbus = max(max(nl), max(nr));
Z = R + j*X;
y= ones(nbr,1)./Z;
Ybus=zeros(nbus,nbus);
for k = 1:nbr;
if nl(k) > 0 & nr(k) > 0
Ybus(nl(k),nr(k)) = Ybus(nl(k),nr(k)) - y(k);
Ybus(nr(k),nl(k)) = Ybus(nl(k),nr(k));
end
end
for n = 1:nbus
for k = 1:nbr
if nl(k) == n | nr(k) == n
Ybus(n,n) = Ybus(n,n) + y(k);
else, end
end
end
% From To R X ---these are from circuit second function
z = [ 1 2 0.12 0.16
2 3 0.032 0.012
3 4 0.001 0.1
3 5 0.002 0.015];
[Ybus] = ybus(z) % bus admittance matrix
Hello,
I would like to choose every element of a matrix with for loop. I mean first I need to select 1st. element then I need to save it to a variable. Then second. thirt... etc.
The matrix that I mention has real and imaginer side in every element. Like;
[Ybus] = ybus(z) % bus admittance matrix
YBara =
3.0000 - 4.0000i -3.0000 + 4.0000i 0.0000 + 0.0000i 0.0000 + 0.0000i 0.0000 + 0.0000i
-3.0000 + 4.0000i 30.3973 -14.2740i -27.3973 +10.2740i 0.0000 + 0.0000i 0.0000 + 0.0000i
0.0000 + 0.0000i -27.3973 +10.2740i 36.2309 -85.7752i -0.1000 + 9.9990i -8.7336 +65.5022i
0.0000 + 0.0000i 0.0000 + 0.0000i -0.1000 + 9.9990i 0.1000 - 9.9990i 0.0000 + 0.0000i
0.0000 + 0.0000i 0.0000 + 0.0000i -8.7336 +65.5022i 0.0000 + 0.0000i 8.7336 -65.5022i
Who can help me? Thank you.
REgards.
0 Kommentare
Antworten (1)
Deepak Meena
am 17 Nov. 2020
Hi,
I think you want to know how you acces the array elements in a for loop. You can refer to this documentations:
0 Kommentare
Siehe auch
Kategorien
Mehr zu Pattern Recognition and Classification finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!