Plotting simple algorithm, problem with axis

Hi
Below my algorithm: First I store the so called Lucas Numbers in a vector v. v contains the N first lucasnumbers. Then I calculate the ratio of the two consequent lucas numbers, i.e. w(1) = v(2)/v(1) etc. and store these results in a vector w with length N-1.
What I want to do next then, is to calculate the absolute value between a defined constant phi and the elements of w and plot them as a function of N-1. But when I try to do so, for the x-axis I never get the range 1:N-1. Why is that?
function plotLucas(N)
% initialize vector v
% v contains the Lucas Numbers
v = zeros(N,1)
v(1) = 1;
v(2) = 3;
for i = 3:size(v,1)
v(i) = v(i-1)+v(i-2)
end
% initialize vector w
% w contains the quotients
w = zeros(N-1,1)
for i = 1:size(w,1)
w(i) = v(i+1)/v(i);
end
phiLucas = (1+sqrt(5))/2
y = abs(w-phiLucas)
plot(y, 1:N-1)
end
Thanks

3 Kommentare

José-Luis
José-Luis am 21 Feb. 2013
Why should you? In your code the x values are the vector y. Or am I missing something?
Azzi Abdelmalek
Azzi Abdelmalek am 21 Feb. 2013
How did you check that?
plot(y, 1:N-1)

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

Thorsten
Thorsten am 21 Feb. 2013

0 Stimmen

Reverse the arguments of plot(x,y)
plot(1:N-1, y)

2 Kommentare

MiauMiau
MiauMiau am 21 Feb. 2013
you are right, what a stupid mistake..thanks
Thorsten
Thorsten am 21 Feb. 2013
If this answered your question, would you please be so kind to accept this answer?

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu 2-D and 3-D Plots finden Sie in Hilfe-Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by