Function outputs NaN for a cell which is assigned a separate value?

I created the following function:

function [x] = f(y)

x = (y==0).*1+(y~=0).*(1./y);

With the following input, it returns this:

f([-3:3])

ans =

   -0.3333   -0.5000   -1.0000       NaN    1.0000    0.5000    0.3333
   

The value should be 1 when y == 0 but it shows NaN instead (assumably by evaluating 1./y when y == 0)

Answer 1

[VBBV]

since you want 1 when y is zero, you need something like

y(y==0) = 1;
y(y~=0) = 1./y;
x = y;