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is there any correction..?

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Lalit Patil
Lalit Patil am 18 Feb. 2013
I am doing Singular value decomposition using this.
Xi = [1 2;3 4]; Yi = [1 2;3 4]; Zi = [1 2;3 4];
A=[Xi,Yi,Zi,ones(length(Xi),1)];
[U S V] = svd(A)
Now, i want to do the same without function. so, i written little as below.
Xi = [1 2;3 4]; Yi = [1 2;3 4]; Zi = [1 2;3 4];
A=[Xi,Yi,Zi,ones(length(Xi),1)];
f = eig(A'*A);
for l = 1:length(f);
p(l) = sqrt(f(l));
end
S = diag(p);
[U,D] = eig(A*A');
[V,D] = eig(A'*A);
V = V';
U
S
But in answer i am getting only some of its elements same in matrix. And remaining are different. So, please suggest any modification if there or solution..?

Antworten (1)

Walter Roberson
Walter Roberson am 20 Feb. 2013
In your second bit of code, your S is a square diagonal matrix, not a diagonal matrix the same size as A.
  1 Kommentar
Lalit Patil
Lalit Patil am 20 Feb. 2013
Bearbeitet: Lalit Patil am 21 Feb. 2013
Then what change to do in S.?
And before S i want to solve problem of U and V.
What change to do in them.?

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