is there any correction..?
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I am doing Singular value decomposition using this.
Xi = [1 2;3 4]; Yi = [1 2;3 4]; Zi = [1 2;3 4];
A=[Xi,Yi,Zi,ones(length(Xi),1)];
[U S V] = svd(A)
Now, i want to do the same without function. so, i written little as below.
Xi = [1 2;3 4]; Yi = [1 2;3 4]; Zi = [1 2;3 4];
A=[Xi,Yi,Zi,ones(length(Xi),1)];
f = eig(A'*A);
for l = 1:length(f);
p(l) = sqrt(f(l));
end
S = diag(p);
[U,D] = eig(A*A');
[V,D] = eig(A'*A);
V = V';
U
S
But in answer i am getting only some of its elements same in matrix. And remaining are different. So, please suggest any modification if there or solution..?
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Antworten (1)
Walter Roberson
am 20 Feb. 2013
In your second bit of code, your S is a square diagonal matrix, not a diagonal matrix the same size as A.
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