using lsqlin when you have a large matrix

hi,
Can someone please tell me how to correct the following code.
x = [yt,r];
a = eye(2);
b = zeros(2,1);
opts = optimset('lsqlin');
opts.LargeScale = 'off';
opts.Display = 'none';
coef = lsqlin(x,yt2,-a,-b);
My x is a 1000*2 matrix. so i get an error. I read the help for that but couldn't understand it clearly.
thanks.

 Akzeptierte Antwort

Teja Muppirala
Teja Muppirala am 18 Feb. 2013

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I don't think there is anything wrong with this code, except LSQNONNEG would be easier.
coef = lsqlin(x,yt2,-a,-b);
is the same as
coef = lsqnonneg(x,yt2);
When I run your core, I don't get any errors at all. I just get
coef =
0.4036
0
Which I have no reason to doubt is a valid answer.
Are you perhaps referring to the warning that comes up regarding the solver?

1 Kommentar

dav
dav am 18 Feb. 2013
Bearbeitet: dav am 18 Feb. 2013
thanks I also figured it out that coef = lsqnonneg(x,yt2) is much easier.

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Weitere Antworten (1)

Matt J
Matt J am 18 Feb. 2013
Bearbeitet: Matt J am 18 Feb. 2013

0 Stimmen

If you have 1000 unknowns why is "a" only 2x2?
Also, since your constraints are only lower bounds on the unknowns, use the lb input argument instead of A,b
Also, since you only have positivity constraints, consider using LSQNONNEG instead of LSQLIN.

6 Kommentare

dav
dav am 18 Feb. 2013
Bearbeitet: Walter Roberson am 18 Feb. 2013
thanks. I am relatively new to matlab. My code is given below. is there any way to correct that code?
a0 = 0.05; a1 = 0.1; b1 = 0.85;
nu = randn(2300,1);
epsi = zeros(2300,1);
h = zeros(2300,1);
for i=2: 2300
h(i) = a0 + a1 * epsi(i-1)^2 + b1 * h(i-1) ;
epsi(i) = nu(i) * sqrt(h(i));
end
yt = zeros(2300,1);
for i=1: 2300
yt(i) = epsi(i)*epsi(i);
end
order = 5;
m = arx(yt, order);
r = resid([yt(1:order);yt], m);
r = r(order+1:end);
yt2 = zeros(2300,1);
for i=1: 2300
yt2(i) = yt(i)- r(i);
end
yt2(1:1300) = [];
yt(1:1299)=[];
yt(1001:1001)=[];
r(1:1299)=[];
r(1001:1001)=[];
x = [yt,r];
a = eye(2);
b = zeros(2,1);
opts = optimset('lsqlin');
opts.LargeScale = 'off';
opts.Display = 'none';
coef = lsqlin(x,yt2,-a,-b);
Walter Roberson
Walter Roberson am 18 Feb. 2013
Even if you only have two constraints that you want to actively make use of, you need to supply values for the others, possibly "inf".
Matt J
Matt J am 18 Feb. 2013
is there any way to correct that code?
As I already mentioned, it is an error to use a 2x2 matrix a=eye(2) and 2x1 vector b=zeros(2,1) when you have more than 2 unknowns.
Teja Muppirala
Teja Muppirala am 18 Feb. 2013
There are not 1000 unknowns, there are only 2. It only seems that way because what the documentation refers to as A, is being called x here, and what the doc refers to as x, is being called coef.
Teja Muppirala
Teja Muppirala am 18 Feb. 2013
Oops I meant C, not A.
Matt J
Matt J am 18 Feb. 2013
There are not 1000 unknowns, there are only 2.
Ah well. The question has been edited.

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