Calculation of antenna efficiency

9 Ansichten (letzte 30 Tage)
Shahar ben ezra
Shahar ben ezra am 5 Nov. 2020
Kommentiert: David Goodmanson am 14 Apr. 2024
How do I calculate antenna efficiency?
The graph gives GAIN (peak Directivity) ,but what is my Directivity?
who can i get efficiency (GAIN/Directivity)
my code:
C = 3*10^8;
F = 10*10^6; %hz
Z0 = 73 ;
Lamda =C/F; %m
ant_short = dipole('Length', Lamda/10 );
ant_Half = dipole('Length', Lamda/2 );
ant_full_wave = dipole('Length', Lamda);
ant_one_and_half_lamda = dipole('Length', Lamda*1.5);
Antenna=ant_Half
pattern(Antenna, F, 0, 0:1:360);
my fig:

Akzeptierte Antwort

David Goodmanson
David Goodmanson am 6 Nov. 2020
Hi Shahar,
The plot is of directivity, not gain (confusingly, directivity is sometimes called directive gain). Since directivity is determined by using the total radiated power, the input power to the antenna does not matter. But to find gain = directivity x [radiated power / input power], the input power must be known. Since this antenna is a theoretical construct, you are free to assume the input power is the same as the radiated power, in which case gain and directivity are the same thing. For a more realistic case you could add resistivity to the antenna elements (not having the antenna toolbox I don't know how the toolbox would give you radiated power vs input power, but I'm sure it will). You could also take the half wave dipole input impedance of 73.1 ohms and assume a mismatch between that value and the output impedance of the driving source. That will lead to wasted power, an antenna efficiency less than 1, and reduced gain.
  3 Kommentare
David
David am 13 Apr. 2024
what?
David Goodmanson
David Goodmanson am 14 Apr. 2024
what indeed?

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Produkte


Version

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by