Help me with for loop

Hi, I have matrix L with dimension 4680*640 and I need to decompose the matrix into 13 submatrix with dimension 360*640

I wrote matlab code but I got this error

" Index in position 2 exceeds array bounds (must not exceed 640). "

where n1=360 and n2=640.

My code is :

for i = 1:1:n1
    for j =1:1:n2
        L1(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(1*n2+1):1:(2*n2)
        L2(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(2*n2+1):1:(3*n2)
        L3(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(4*n2+1):1:(4*n2)
        L4(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(5*n2+1):1:(5*n2)
        L5(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(6*n2+1):1:(6*n2)
        L6(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(7*n2+1):1:(7*n2)
        L7(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(8*n2+1):1:(8*n2)
        L8(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(9*n2+1):1:(9*n2)
        L9(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(10*n2+1):1:(10*n2)
        L10(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(11*n2+1):1:(11*n2)
        L11(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(12*n2+1):1:(12*n2)
        L12(i,j) = L(i,j);
    end
end

for i = 1:1:n1
    for j =(13*n2+1):1:(13*n2)
        L13(i,j) = L(i,j);
    end
end

Answer 1

[Stephen23]

Rather than writing so much code and using numbered variables (very bad data design), you should just use mat2cell:

L = rand(4680,640); % fake data
idr = 360*ones(1,13);
idc = 640;
out = mat2cell(L,idr,idc);
size(out)

ans = 1×2

13 1

●

You can access the cell array contents using basic and very efficient indexing:

out{1} % the 1st matrix
out{2} % the 2nd matrix
etc.

https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html

[Mohammad Alwardat]

Thanks, it's work.

I'm a beginner in MATLAB so I always write bad codes :(