How get adjacency matrix from this code

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Konstantinos koutsikakis
Konstantinos koutsikakis am 30 Okt. 2020
Kommentiert: Walter Roberson am 1 Nov. 2020
N = input('no. of Nodes');
p = input('Give the possibility');
m = (n*(n-1))/2;
degree=zeros(N,1);
position=zeros(N,2);
for m=1:N
position(m,1)=cos(m/N*2*pi);
position(m,2)=sin(m/N*2*pi);
end
hold on;
plot(position(:,1),position(:,2),'d')
for m=1:N
for n=m+1:N
if(rand(1,1)<p)
degree(m,1)=degree(m,1)+1;
degree(n,1)=degree(n,1)+1;
plot(position([m,n],1),position([m,n],2))
end
end
end
hold off;

Antworten (1)

Stephan
Stephan am 31 Okt. 2020
Bearbeitet: Stephan am 31 Okt. 2020
I would recommend to use the inbuilt functions for working with graphs - it makes life much easier:
N = input('no. of Nodes');
p = input('Give the possibility');
% Make adjacency matrix
idx = find(triu(ones(N),1));
V = rand(((N-1)*N)/2,1)<p;
A = zeros(N);
A(idx) = V;
A = A + triu(A,1)';
% create and plot undirected graph object
g = graph(A)
plot(g)
A good start for reading is here:
  4 Kommentare
Konstantinos koutsikakis
Konstantinos koutsikakis am 1 Nov. 2020
ok. how to print points in the form of a circle and a adjacency matrix
Walter Roberson
Walter Roberson am 1 Nov. 2020
https://www.mathworks.com/help/matlab/ref/matlab.graphics.chart.primitive.graphplot.layout.html#d122e485652

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