While-Loops display each iteration of a variable

I am very new to MATLAB, so bear with me please.

I'm working on a school assignment regarding while loops and I am required to print a tally of all entered x values after the loop has ended, I have no clue how to do that however.

This is the assignment:

1. Using different variable names than in the examples above, write a script to let the user type in values from the keyboard and sum them up. This time make the script only total up zeroes or negative values. If a positive value is entered the script should stop at that time. Or, if a negative value less than 500, such as -501 is entered, the script is to stop. When the script stops, give the tally, and in a separate statement indicate what caused the program to end.

This is an example of what should show up after the loop has ended:

-491

-12

0

Total = -503

A positive value of 5 was entered and stopped the summation.

(Or, a value of -682 was entered and stopped the summation.)

This is what I have:

clear
clc 

fprintf(' This script will take an x value, as long as it is larger than -501,')
fprintf('\n      and less than 1, and will add it to the previous x value.\n\n')

sum = 0;
a = -500;

x = input(' Enter a value greater than -501 and less than 1: ');

while ( 0 >= x ) && ( x >= a )
          
   
    
 sum = sum + x;
       
 x = input(' Enter another value greater than -501 and less than 1: ');
           
end

%????????? need each new x value to show here 
%    x 1st loop
%    x 2nd loop
%    x 3rd loop
%    ... 

fprintf( 'Total = ')
fprintf( '%.f' , sum)

if  ( x > 0)
    
    fprintf('\n\nLoop ended, a positive value of ')
    fprintf("%.f" , x)
    fprintf(' was entered \n\n')

end

if ( x < a )

    fprintf(' Loop ended, a negative value of ')
    fprintf("%.f" , x)
    fprintf(' was entered \n\n')
end

Answer 1

[Daniil Hart]

Never mind, I tinkered and used I guess a sort of counter within the loop to produce a new variable?

sum = 0;
a = -500;

x = input(' Enter a value greater than -501 and less than 1: ');

n = 1;     % counter variable starting at 1

while ( 0 >= x ) && ( x >= a )
          
 
     
 
 sum = sum + x;
       
 x = input(' Enter another value greater than -501 and less than 1: ');
 
 n = n+1;   % counter increasing 
 
 b(n)=x;    % new variable that is a vector that grows in columns with each loop
 

 
end

b = b';

fprintf('\n All entered values of x:\n')
disp(b)

Answer 2

[Ayesha]

n=5
fac=1
while(n>=1)
    n=n-1
    fac=fac*n
end

[DGM]

Use semicolons to suppress output..

% use a unique name for the parameter
% so that it doesn't get lost
n0 = 5;

% you could use a while loop,
% but while loops are more complicated and have extra hazards
fac = 1;
n = n0;
while n >= 1
    fac = fac*n;
    n = n-1; % order of operations!
end
fac

fac = 120

% but there's no good reason to use a while loop
% if the number of iterations are known
fac = 1;
for n = 1:n0
    fac = fac*n;
end
fac

fac = 120

% you could eliminate the loop completely with basic vectorization
fac = prod(1:n0)

fac = 120

% or you could just use factorial()
fac = factorial(n0)

fac = 120