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Calling the set of images in subfolder from augmented image datastore

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Rd am 30 Okt. 2020
I have the database contain 180 images in per subfolder. I have 10 subfolder. I have to assign first 60 images in each subfolder to XTrain1, next 60 images in each subfolder to XTrain2, next 60 images in each subfolder to XTrain3.
i have included my code here. Kindly help me to loop the folders.
imagefolder = 'C:\Users\manjurama\Desktop\study\PG\PROJECT\Finger vein database multiple copy\database_10';
imds = imageDatastore(imagefolder,'IncludeSubfolders',true,'LabelSource','foldernames');
numTrainFiles = 0.75;
imageSize = [227 227];
[XTrain,YTrain] = splitEachLabel(imds, numTrainFiles,'randomize');
XTrain = augmentedImageDatastore(imageSize,XTrain);
YTrain = augmentedImageDatastore(imageSize,YTrain);

Antworten (1)

drummer am 30 Okt. 2020
Bearbeitet: drummer am 30 Okt. 2020
By your last three lines, you can do the following:
Xtrain1 = XTrain.Files(1:60);
XTrain2 = XTrain.Files(61:120);
XTrain3 = XTrain.Files(121:160);
As you see, you're taking advantage of the augmentedImageDataStore properties. The Files, specifically. You can check them by typing your augmented variable in the command window:
>> XTrain
This is a workaround. You should work on getting each of your training files from different folders at different indexes as you mentioned.
  6 Kommentare
Rd am 11 Nov. 2020
Dear drummer,
As you mentioned before, i split my imagefolder into training and testing image like
This is the code i have used
imagefolder = 'C:\Users\manjurama\Desktop\training and testing\Training';
XTrain = imageDatastore(imagefolder,'IncludeSubfolders',true,'LabelSource','foldernames');
[XTrain1,XTrain2,XTrain3] = splitEachLabel(XTrain, 0.33,0.33, 0.33, "randomized");
YTrain = XTrain1.Labels;
the database is splitted. But the issue is i couldn't assign the folder name as label.
While using the above code, file name as assigned as labels. hence it shows 180 labels.
i need to the labels(=YTrain) as class1, class2,....class10.
Kindly help me to solve this issue. Thanks.

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