size mismatch in matlab function block
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chuyen hoangcao
am 28 Okt. 2020
Bearbeitet: Walter Roberson
am 29 Okt. 2020
i dont know why there are some errors about size mismatch in my code, because as you can see, variable s has dimension is [1,2],Cl is [2,2] .Therefore i think the result will be [1,2] ,but it doesnt work.Please help me.
My code:
function [Cl,gl,ds] = fcn(q1,q2,dq2,dq1, Tl,Th,de,e,s,t)
%Matrices of dynamic equation.
a = 1.024;b = 0.24;Ro = 0.16;
g = 9.8;
Ml = [a+2*b*cos(q2) Ro+b*cos(q2); Ro+b*cos(q2) Ro];
Cl = [-2*b*sin(q2)*dq2 -b*sin(q2)*dq2; b*sin(q2)*dq1 0];
gl = [2.5*g*Ro*cos(q1+q2)+1.67*0.864*cos(q1) 2.5*g*Ro*cos(q1+q2)];
lamda = 0.6; ep = 3;d =1.2;
theta = [0.99; 0.12];
wl = 0.3+0.2*sin(2*t)+0.3*sin(20*t) - 0.2*sin(10*t)+ 0.3*sin(21*t);
w0 = 0.2 + 0.3*sin(15*t);
% dieu kien cua w estimation
if norm(s) > ep
Row = d*s./norm(s);
else
Row = d*s./ep;
end
we = w0 + Row;
% el(t) = -e(t);
Yl =( - de*Ml*lamda - e*Cl*lamda +gl);
ds =(-de*Ml*lamda -s*Cl - Yl*theta -(2*we-wl)+Tl+Th).*inv(Ml);
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Fangjun Jiang
am 28 Okt. 2020
Bearbeitet: Fangjun Jiang
am 28 Okt. 2020
[1 2]*[2 2; 2 2] is correct.
[1 2].*[2 2; 2 2] is wrong (without implicit expansion)
3 Kommentare
Fangjun Jiang
am 28 Okt. 2020
take a particular set of values for all the input arguments, run the code line by line, stop at the line where the error occured, run indivudual section of that line of code if necessary, you will find where and what caused the error.
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