How to fix it.

wav dimentions are

wav = 5001*1

and I want to change it as wav = 5001*5

How I can reshape it?

Answer 1

[Steven Lord]

So you want to take 5001 values and generate 25005 (5001 times 5) values using those values. How do you want to generate the additional 20004 values?

Make duplicate copies?

x = (1:6).'
y = repmat(x, 1, 5)

Offset the copies by a certain amount? This approach uses implicit expansion; if you're using an older release you could use bsxfun.

x = (1:6).'
y = x + (0:10:40)

Pad with 0 values or with random data?

x = (1:6).'
y = [x, zeros(size(x, 1), 5)]
z = [x, rand(size(x, 1), 5)]
w = [x, randi([7 11], size(x, 1), 5)]

Something else? If so, please explain in detail how you want to generate the additional values.

[Nisar Ahmed]

I want to generate duplicate values (5000) in five columns rather than one...

[Elijah McNeil]

His code does that, Just write this.

x = (1:5000).';
wav = repmat(x, 1, 5).

[Nisar Ahmed]

Elijah McNeil, thanks dear, Now it is working

Answer 2

[Elijah McNeil]

This should work

wav = 5001*1
wav = wav*5

[Nisar Ahmed]

In wav, it is one column matrix and I want to convert it into 5 column matrix...

[Elijah McNeil]

OK, you can't do that unless wav has 5 values. Example:

wav = [5000; 6000;7000; 8000; 9000] % that equals 1 column and 5 rows
wav = wav' % that creates 5 columns and 1 row
reshape(wav,1,5) % this also creates 5 columns and 1 row

[Nisar Ahmed]

It is not working, perhaps I'm unable to explain my point...

the size of wav is 5000 1 and I want reshap it as 5000 5

[Elijah McNeil]

Wait 5000 rows and 1 column?

[Nisar Ahmed]

5000 rows and 5 columns, each column is duplicate of other.