Extract data from a csv file in Matlab
Ältere Kommentare anzeigen
Hello,
I am trying to open csv file in Matlab (2020) and extract the data, then put the first column of the data in three columns, year, month day hour.
The data in the csv file attached.
I am using the code below but it is not working. It extracts columns with NaN values. Could you please help me with this? Thanks
fileID = fopen('AberSARAHsolar30deg0deg2012.csv','rt')
C=textscan(fileID,'%s %s %s %s %s %s %s %s ','delimiter',',');
fclose(fileID)
%EXTRACT
time =C{1}(2:end);
Gizero = str2double(C{2}(2:end));
T2m=str2double(C{4}(2:end));
WS10m = str2double(C{5}(2:end));
Githirty =str2double(C{8}(2:end));
%EXTRACT TEXT TO YEAR MONTH DAY HOUR
formatIn ='yyyy-mm-dd hh';
DATETIME=datevec(time,formatIn);
YMDH=DATETIME(:,1:4);
1 Kommentar
dpb
am 28 Okt. 2020
Use readtable instead...
Convert the time string to datetime
Antworten (1)
Walter Roberson
am 28 Okt. 2020
formatIn ='yyyymmdd:HHMM';
It is questionable as to whether that is the correct format, however. Each of the entries ends in 11 . It is not impossible that each of them was taken at exactly 11 minutes after each hour, but it would be uncommon.
Kategorien
Mehr zu String Parsing finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!