count of non zero elements of a row vector in a loop

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Georgios Kirkinezos
Georgios Kirkinezos am 28 Okt. 2020
Kommentiert: Peter O am 28 Okt. 2020
Hi everyone,
i want to count the nonzero elements of a row-vector in a loop, i have the initial (360,1000) matrix u_new
for i=1:360;
for j=1:1000;
if u_new(i,j)==0 %%% here i transformed zeros to Nan, to use the following command isnan
u_new(i,j)=NaN;
insample_u_new=isnan(u_new(i,:))==0; %%% in this row-vector the possible values are 0 or 1, i am interested in getting the number of ones
P = numel(insample_u_new(i,j)~= 0); %%%here is the problem
end
end
end
I want the output P to be the number of the nonzero elements (ones) from the row-vector u_new=u(:,1:1000) for the loop.
Thanks for your answers in advance.

Akzeptierte Antwort

Peter O
Peter O am 28 Okt. 2020
Try the nnz function.
It sounds like you're trying to count the number of nonzero elements in each row? Use arrayfun to apply this function to each row of the matrix (extracting the row index).
NZ = arrayfun(@(ix) nnz(u_new(ix,:)),1:size(u_new,1))
NZ will be a 1 x n_rows vector containing the nonzero element counts for each row.
  2 Kommentare
Georgios Kirkinezos
Georgios Kirkinezos am 28 Okt. 2020
I used the following command and it worked for my code based on nnz as you mentioned
NZ(i) = nnz(insample_u_new);
Peter O
Peter O am 28 Okt. 2020
Glad to hear it worked for your use!

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KSSV
KSSV am 28 Okt. 2020
Read about nnz.

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