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How to convert a vector of integers to a vector of characters?

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Hi - I have a vector of ints, typically 0/1, like this:
[0 0 0 0 1 0 0 0 0 1]
and I want to get this:
['0' '0' '0' '0' '1' '0' '0' '0' '0' '1']
But I cannot figure it out for the life of me. I'm sure it's simple. Thanks for your time and help.

Akzeptierte Antwort

James Tursa
James Tursa am 10 Feb. 2013
Another method for single digits:
A = [0 0 0 0 1 0 0 0 0 1];
B = char(A+'0');

Weitere Antworten (3)

Wayne King
Wayne King am 9 Feb. 2013
Bearbeitet: Wayne King am 9 Feb. 2013
A = [0 0 0 0 1 0 0 0 0 1];
B = num2str(A);
Now B is a vector of characters
  2 Kommentare
Michael
Michael am 9 Feb. 2013
Hi Wayne -- I knew of num2str and tried that, but it turns out you're right. But what I figured out was that it was the extra spaces in the result of num2str that was throwing me off. i.e. num2str([0 0 0 0 0]) = '0 0 0 0 0', which is length 9 or something (but not 5). I removed the spaces from the result of num2str and it worked great. Thanks for the help.

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Azzi Abdelmalek
Azzi Abdelmalek am 9 Feb. 2013
Bearbeitet: Azzi Abdelmalek am 9 Feb. 2013
a = [0 0 0 0 1 0 0 0 0 1];
y=arrayfun(@(x) cellstr(num2str(x)),a)
% To get any character
y{4} % for e.g

Jan
Jan am 10 Feb. 2013
Bearbeitet: Jan am 10 Feb. 2013
Instead of removing the spaces from the output of num2str, you can create string without spaces directly:
a = [0 0 0 0 1 0 0 0 0 1];
s = sprintf('%d', a);
Another fast but more strange method is:
s = char('0' + a);

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