Delete a cell by a criterion???

3 Ansichten (letzte 30 Tage)
Thor
Thor am 5 Feb. 2013
Dear all,
I have a cell array of 31x12x9 and in every cell is a 288x3 structure. I want to delete every cell wich has not the 288x3 structure. So all have x3 but the value 288 is in some cells different and these should be deleted! Thank you in advance!

Akzeptierte Antwort

Conrad
Conrad am 5 Feb. 2013
Hi Thor, try the following:
% Create dummy data.
S = cell(1,2,2);
l1(288,3).Value = 1; l2(280,3).Value = 1;
S{1,1,1} = l1; S{1,1,2} = l2; S{1,2,1} = l1; S{1,2,2} = l1;
K = S(cell2mat(cellfun(@(x) size(x,1), S, 'UniformOutput', false))==288);
Conrad

Weitere Antworten (2)

Youssef  Khmou
Youssef Khmou am 5 Feb. 2013
Your cell array is A of size m=31, n=12 , p=9 :
for x=1:m
for y=1:n
for z=1:p
if(size(A{x,y,z},1)~=288 && size(A{x,y,z},2)~=3)
A{x,y,z}=[];
end
end
end
end

Jan
Jan am 5 Feb. 2013
Bearbeitet: Jan am 5 Feb. 2013
If C is your data cell:
C(cellfun('size', C, 1) ~= 288) = {[]};
Here the contents of the not matching cell elements are deleted, but not the cells itself. If you want to delete the cells, the result cannot be a cell array anymore but a cell vector only:
C = C(cellfun('size', C, 1) == 288);

Kategorien

Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by