Problem with a function
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Paul Rogers
am 21 Okt. 2020
Kommentiert: Paul Rogers
am 24 Okt. 2020
Hello everyone, I wrote this function:
function dz = nocontrol(v,z,parameters)
gammaT=??????????;
phi_0 =0.6;
psi_0 =0.6857;
psi_c0 = 0.3;
B=1.8;
Lc = 3; %m
W = 0.25;
H = 0.18;
C = 0;
dz = zeros(2,1);
dz(1)=(1/(4*B*B*Lc))*(z(2)-gammaT*(z(1))^0.5);
psi_c=psi_c0+H*(1+1.5*(z(2)/W-1)-0.5*(z(2)/W-1).^3);
dz(2) =(1/Lc)*(psi_c-z(1));
end
my problem is that I don't know how to write properly gammaT. I'd like to express it as a function, something like this:
gammaT_max = 0.8;
gammaT_min = 0.7;
A = (gammaT_max - gammaT_min)/2; %amplitude
b = gammaT_max - ((gammaT_max - gammaT_min)/2);
gammaT = A*sin(w*t)+b
but I don't know how.
2 Kommentare
madhan ravi
am 21 Okt. 2020
what's your question? Are you asking if the way you defined the gamma function is correct?
Akzeptierte Antwort
Walter Roberson
am 21 Okt. 2020
You have defined gammaT as a variable that you multiply by, but it needs to be a function of time. You will likely need something like
gammaT = @(t) A*sin(w*t)+b
dz(1)=(1/(4*B*B*Lc))*(z(2)-gammaT(SOMETHING)*(z(1))^0.5);
The SOMETHING would have to be replaced with your time variable, but it is not obvious that you have a time variable. Perhaps v is your time variable.
3 Kommentare
Walter Roberson
am 22 Okt. 2020
You do not have a time variable, so I had to substitute the closest I could find.
function dz = nocontrol(v,z,parameters)
gammaT=parameters(1);
phi_0=parameters(2);
psi_0=parameters(3);
psi_c0=parameters(4);
B=parameters(5);
Lc=parameters(6);
W=parameters(7);
H=parameters(8);
C = 0;
gammaT_max = 0.8;
gammaT_min = 0.7;
A = (gammaT_max - gammaT_min)/2; %amplitude
b = gammaT_max - ((gammaT_max - gammaT_min)/2);
gammaT = @(t) A*sin(W*t)+b
dz = zeros(2,1);
dz(1)=(1/(4*B*B*Lc))*(z(2)-gammaT(v)*(z(1))^0.5);
psi_c=psi_c0+H*(1+1.5*(z(2)/W-1)-0.5*(z(2)/W-1).^3);
dz(2) =(1/Lc)*(psi_c-z(1));
end
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