w= 1 0 1
w= 0 1 1
w= 0 1 0
how came this can be written in straight line
w= 1 0 1 0 1 1 0 1 0

 Akzeptierte Antwort

Walter Roberson
Walter Roberson am 24 Apr. 2011

0 Stimmen

You might find this easier to understand:
w = []; for i = 1:30 w = [w, A(i), B(i), C(i)]; end

2 Kommentare

Oleg Komarov
Oleg Komarov am 24 Apr. 2011
Seriously :)?
Walter Roberson
Walter Roberson am 24 Apr. 2011
Yup. Get it working first, and *then* optimize it.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 24 Apr. 2011

0 Stimmen

It cannot. The first one assigns the row vector [0 1 0] to w, but the second one assigns a row vector of length 9 to w.
If your original data is a 3 x 3 matrix instead, then
w = reshape(w.',1,numel(w));

7 Kommentare

mahaveer hanuman
mahaveer hanuman am 24 Apr. 2011
not working
mahaveer hanuman
mahaveer hanuman am 24 Apr. 2011
those 'w' are vectors
Walter Roberson
Walter Roberson am 24 Apr. 2011
What *exactly* do you have for input? And what *exactly* do you want for output?
w = 1 0 1
is not valid MATLAB input.
mahaveer hanuman
mahaveer hanuman am 24 Apr. 2011
for i=1:30;
w=([A(i),B(i),Q(i)]);
end
after perfoming this
i got out put as
w=
1 0 1
w=
0 0 1
w=
1 1 1
and so on.........................
now i need to make them into one single bit stream
like
w=1 0 1 0 0 1 1 1 1 .....................
Oleg Komarov
Oleg Komarov am 24 Apr. 2011
Preallocate before the loop:
w = zeros(1,30*3);
for ...
w(i*3-2:i*3) = ([A(i),B(i),Q(i)]);
end
Walter Roberson
Walter Roberson am 24 Apr. 2011
N = 30;
w = reshape([reshape(A(1:N),1,N); reshape(B(1:N),1,N); reshape(C(1:N),1,N)], 1, 3*N);
The above does not assume that A, B, or C are row vectors or column vectors. If the shapes are known and consistent, the code can be simplified -- especially if you are putting together _all_ of the vector instead of just a subset of it.
For example, if they are all row vectors and you are using all of them, then
w = [A;B;C]; w = w(:).';
mahaveer hanuman
mahaveer hanuman am 24 Apr. 2011
thanks its working

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Physics finden Sie in Hilfe-Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by