For each random point, keep the random point if it is in the triangular region having vertices (0,0), (b,0) and (b,h), and if the random point is not in the triangular region, preform the appropriate transformation on the point to create a point that is in the triangular region.
Randomly chooses points from a triangular region and stores the x and y coordinates
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My task is to write a MATLAB function where b and h are positive real numbers, n is a positive integer, and x and y are row vectors of length n. Program will randomly choose n points from the triangular region having vertices (0,0), (b, 0) and (b,h) and stores the x-coordinates and y-coordinates of the n points in the x and y vectors respectively in the order the points are chosen. I have a program written out that produces y-values, but I am not sure how to get both x and y values from the program.
Here is what I have so far:
function [x,y] = hw22(b,h,n)
%
rng('shuffle')
x = zeros(1,n);
y = zeros(1,n);
k = 1;
while k <= n
x(k) = h*rand;
y(k) = b*rand;
if y(k) < b/h*x(k)
k = k + 1;
end
end
Antworten (5)
Asad (Mehrzad) Khoddam
am 12 Okt. 2020
function [x,y] = hw22(b,h,n)
%
rng('shuffle')
x = zeros(1,n);
y = zeros(1,n);
k = 1;
while k <= n
xr = h*rand;
yr = b*rand;
if yr < b/h*xr
x(k)=xr;
y(k)=yr;
k = k + 1;
end
end
0 Kommentare
Ameer Hamza
am 12 Okt. 2020
Bearbeitet: Ameer Hamza
am 12 Okt. 2020
The code seems correct, just swap the h and b
[x, y] = hw22(1, 2, 1000);
plot(x, y, '+');
function [x,y] = hw22(b,h,n)
%
rng('shuffle')
x = zeros(1,n);
y = zeros(1,n);
k = 1;
while k <= n
x(k) = b*rand;
y(k) = h*rand;
if y(k) < h/b*x(k)
k = k + 1;
end
end
end

Bruno Luong
am 12 Okt. 2020
Bearbeitet: Bruno Luong
am 12 Okt. 2020
This is a direct method, no loop, no discard, etc...
n = 1e4;
b = 1;
h = 2;
w1=1-sqrt(rand(1,n));
w2=(1-w1).*rand(1,n);
w3=1-(w1+w2);
w=[w1;w2;w3];
% triangle coordinates
Txy =[0, b, b;
0, 0, h];
Rxy = Txy*w;
x = Rxy(1,:);
y = Rxy(2,:);
% Check
plot(x,y,'.')
0 Kommentare
Asad (Mehrzad) Khoddam
am 12 Okt. 2020
function [x,y] = hw22(b,h,n)
x=rand(n,1)*b;
y=rand(n,1).*x*h/b;
end
1 Kommentar
Asad (Mehrzad) Khoddam
am 13 Okt. 2020
function [x,y] = hw22(b,h,n)
x=rand(n,1)*b;
y=rand(n,1)*h;
ind=find(y>x*b/h);
x(ind)=b-x(ind);
y(ind)=h-y(ind);
end
0 Kommentare
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