Combining two different size variables into one matrix
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Daria Ivanchenko
am 8 Okt. 2020
Kommentiert: Daria Ivanchenko
am 8 Okt. 2020
Hi!
I have two variables of different size. Let's suppose A is the size of 1x5 and B is the size of 1x8. I want to make a matrix where the first row will be A, and the second raw will be B. The matrix should be the size of 2x8 where the last columns of the first row are replaced with NaNs. For example:
A = [1 2 3 4 5]
B = [1 2 3 4 5 6 7 8]
C = [1 2 3 4 5 NaN NaN NaN; 1 2 3 4 5 6 7 8]
How can I do this?
Thanks!
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Akzeptierte Antwort
Stephen23
am 8 Okt. 2020
The simplest solution is to download this:
and then all you need is this:
>> A = [1,2,3,4,5];
>> B = [1,2,3,4,5,6,7,8];
>> C = padcat(A,B)
C =
1 2 3 4 5 NaN NaN NaN
1 2 3 4 5 6 7 8
Weitere Antworten (1)
Ameer Hamza
am 8 Okt. 2020
Bearbeitet: Ameer Hamza
am 8 Okt. 2020
Try this
A = [1 2 3 4 5];
B = [1 2 3 4 5 6 7 8];
M = {A, B}; % combine all variables in a cell array
n = max(cellfun(@numel, M));
M = cellfun(@(x) {[x nan(1,n-numel(x))]}, M(:));
C = cell2mat(M);
3 Kommentare
Ameer Hamza
am 8 Okt. 2020
My code works in this case too
A = [1 2 3 4 5 6 7 8; 1 2 3 4 5 NaN NaN NaN];
B = [1 2 3 4 5];
M = {A, B};
n = max(cellfun(@(x) size(x, 2), M));
M = cellfun(@(x) {[x nan(1,n-numel(x))]}, M(:));
C = cell2mat(M);
Result
>> C
C =
1 2 3 4 5 6 7 8
1 2 3 4 5 NaN NaN NaN
1 2 3 4 5 NaN NaN NaN
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