How to make sigma from my problem using math lab code?
17 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I want to calculate eval (x (pop_size)) = sigma (c (i, j) * x (i, j)) where i = 1 to m and j = 1 to n and I also want to calculate F = sigma ( eval (x (pop_size))) with pop-size = 1 up to pop_size = 25 with the following mathlab code
op_size = 5;
%sigma=0
%q=0
for count = 1:pop_size
%fprintf('count =%d\n',count);
c = [10 2 20 11
12 7 9 20
4 14 16 18];
[m,n] = size(c);
phi = 1:m*n;
s = [15
25
10
];
d = [5 15 15 15];
for count2=1:length(phi)
% fprintf('count2=%d\n',count2);
used_idx = randi(length(phi));
trial = phi(used_idx);
phi(used_idx) = [];
i = [1+mod((trial-1),m)];
j = [1+mod((trial-1),n)];
x(i,j) = min(s(i),d(j));
s(i) = s(i)-x(i,j);
d(j) = d(j)-x(i,j);
Eval=0;
for j=1:n
for i=1:m
if x(i,j)>0
Eval=Eval+c(i,j)*x(i,j);
%fprintf('Eval=%d\n',Eval);
end
end
end
end
disp(Eval)
end
i use the sum function but the result is not what i want ...
4 Kommentare
Antworten (1)
Walter Roberson
am 8 Okt. 2020
op_size = 5;
%sigma=0
%q=0
all_Evals = zeros(pop_size,1);
for count = 1:pop_size
%fprintf('count =%d\n',count);
c = [10 2 20 11
12 7 9 20
4 14 16 18];
[m,n] = size(c);
phi = 1:m*n;
s = [15
25
10
];
d = [5 15 15 15];
for count2=1:length(phi)
% fprintf('count2=%d\n',count2);
used_idx = randi(length(phi));
trial = phi(used_idx);
phi(used_idx) = [];
i = [1+mod((trial-1),m)];
j = [1+mod((trial-1),n)];
x(i,j) = min(s(i),d(j));
s(i) = s(i)-x(i,j);
d(j) = d(j)-x(i,j);
Eval=0;
for j=1:n
for i=1:m
if x(i,j)>0
Eval=Eval+c(i,j)*x(i,j);
%fprintf('Eval=%d\n',Eval);
end
end
end
end
disp(Eval)
all_Evals(count) = Eval;
end
sum_of_Evals = sum(all_Evals);
0 Kommentare
Siehe auch
Kategorien
Mehr zu Arduino Hardware finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!