Loop Updating Vectors for Number of Iterations

4 Ansichten (letzte 30 Tage)
Denzel Philip Belleza
Denzel Philip Belleza am 7 Okt. 2020
Hello,
I am trying to create a loop that will update a vector for a given number of iterations but keep getting errors. The x0 vector is solved and I would like to set as the first iteration. I would appreciate any help :)
What I am Trying to Implement:
x0 = A\b
x1 = A\x0
x2 = A\x1
...
xn = A\x(n-1)
My Code:
clear, clc;
% Given Information
A = [3 2 3; 5 5 6; 9 8 9];
b = [1; 2; 3];
x0 = A\b; % Calculate x0 vector
% My Attempt at Loop
b_ = zeros(size(b)); % Initialize?
x_ = zeros(size(x0)); % Initialize?
for k = 1:200
x(k(1)) = x_ + x0 % First Iteration
b(k) = b_ + x(k) % Update b vector
x(k+1) = A\b(k) % Updated x vector
end
  2 Kommentare
Walter Roberson
Walter Roberson am 7 Okt. 2020
Is it correct that your b is always the previous x (except for the first time) ? Your use of those updates with 0 is confusing the issue if they are not needed.
Denzel Philip Belleza
Denzel Philip Belleza am 7 Okt. 2020
Hi Walter,
Yes, I am trying to have b always updated to the previous x.

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Asad (Mehrzad) Khoddam
Asad (Mehrzad) Khoddam am 7 Okt. 2020
Simply use
A = [3 2 3; 5 5 6; 9 8 9];
b = [1; 2; 3];
x=b;
for k=1:200
x=A\x;
end

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by