I have a matrices (b1 and popx) with size 25000x50000, code is a vector which contains unique values in b1 (of length 300). For elements in popx which correspond to each unique value of b1, I need the sum of popx,
The below code takes very long (>2 hours) to operate, Any help to lower computation time is much appreciated
for i=1:300
popx1=popx;
popx1(b1~=code(i))=NaN;
popn=nansum(nansum(popx1));
popn1(i)=popn;
end;

 Akzeptierte Antwort

Jos (10584)
Jos (10584) am 6 Okt. 2020

1 Stimme

Pre-allocation, and recoding using logical indexing and sum should speed things up
popn1 = nan(300,1) ; % pre-allocation
for i=1:300
tf = b1 == code(i) ;
popn1(i) = sum(popx(tf), 'all') ;
end;

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Hilfe-Center und File Exchange

Gefragt:

am 6 Okt. 2020

Kommentiert:

am 6 Okt. 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by