Count the number of times a value appears in a row and save the row number
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James Peach
am 6 Okt. 2020
Kommentiert: Star Strider
am 6 Okt. 2020
I wanted to sort points in an array based on how many times a number less than or equal to 1.5 appears in the row. I want to save the row index number of those that have 3 or more occurences less than or equal to the target value of 1.5. I have placed the array below. If you have any ideas on how to do this that would be great. Thanks for your time.
A = [NaN 1.00000000000000 1.00000000000000 1.99994495218295 1.40991828545270 1.98465118243128 2.97995391814023 1.41286932041226 1.44150019470391 2.30703739193881
1.00000000000000 NaN 1.41618367600370 0.999999999999996 1.00000000000000 2.11349467948903 1.98589244648483 1.00000000000000 1.73544845449717 1.98611502337309
1.00000000000000 1.41618367600370 NaN 2.24512987514306 2.20570040562793 0.999999999999996 3.22884118121504 1.75480404405606 1 3.15259384660772
1.99994495218295 0.999999999999996 2.24512987514306 NaN 1.40867173007472 2.65578172203034 1.00000000000000 1.41514975278174 2.44463958996392 2.12446752335984
1.40991828545270 1.00000000000000 2.20570040562793 1.40867173007472 NaN 3.01897607767301 2.11695260794737 1.62219494319153 2.57847672580517 1.00000000000000
1.98465118243128 2.11349467948903 0.999999999999996 2.65578172203034 3.01897607767301 NaN 3.52998354037453 2.38833466800397 1.41223022448087 3.96751962825988
2.97995391814023 1.98589244648483 3.22884118121504 1.00000000000000 2.11695260794737 3.52998354037453 NaN 2.21498386821498 3.35954605769311 2.49207458085697
1.41286932041226 1.00000000000000 1.75480404405606 1.41514975278174 1.62219494319153 2.38833466800397 2.21498386821498 NaN 1.44673037867744 2.53341581840774
1.44150019470391 1.73544845449717 1 2.44463958996392 2.57847672580517 1.41223022448087 3.35954605769311 1.44673037867744 NaN 3.56150161869124
2.30703739193881 1.98611502337309 3.15259384660772 2.12446752335984 1.00000000000000 3.96751962825988 2.49207458085697 2.53341581840774 3.56150161869124 NaN];
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Akzeptierte Antwort
Star Strider
am 6 Okt. 2020
Try this:
rowsum = sum((A <= 1.5), 2);
result = find(rowsum >= 3)
producing:
result =
1
2
3
4
5
8
9
Those could be combined into one line:
result = find(sum((A <= 1.5), 2) >= 3)
I kept them separate for clarity.
4 Kommentare
Star Strider
am 6 Okt. 2020
That’s what I thought, although I wanted to explain the other options.
As always, my pleasure!
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