1x10 matrix using a single while loop

n = 10;
A =zeros(1,n);
count=1;
while i==1 && j==1:n;
count=count+1;
A(i,j)=count;
  end
display(A)

trying to get this to display A=[1 2 3 4 5 6 7 8 9 10] using exactly 1 while loop.

[Walter Roberson]

while i==1 && j==1:n;

j==1:n is a vector comparison, with a vector result (length 10). You cannot use a vector together with the && operator.

Also, your while loop does not change i or j, so your loop would be infinite if it was accepted at all.

Answer 1

[Pink_panther]

n=10;A =zeros(1,n);k=1;
while k <=n
    A(k)=k
    k=k+1;
end

Answer 2

[Walter Roberson]

variable = initial_value;
while variable <= final_value
    do something with variable
    variable = variable + increment;
end

Answer 3

[Pink_panther]

OP was asking for one liner.

Here is the shorter verion, it worked on my PC.

n=10;A=[];k=1;while k <=n,A=cat(2,A,k),k=k+1;end

[Rik]

You didn't format this as code, and it actually performs worse than your other answer, because it dynamically grows the array. Other than that it is identical to your other answer. What would be the benefit? Compressing code into a one-liner doesn't usually improve code readibility and doesn't change performance.

[Walter Roberson]

The poster asked for exactly one while loop, but did not ask for a one-liner.