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Do not take any amount

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lech king
lech king am 5 Okt. 2020
Kommentiert: lech king am 5 Okt. 2020
pop=randi([100],20,8);
[r1,c1]=size(pop);
for i=1:r1
A=randi(100);
if A<=90
pool(i,:)=pop(i,:);
end
end
Hi
I want if the condition is not met, the pool variable does not take any value, in other words, in the end, for example, it becomes an 18x8 matrix, not an 20x8 matrix with 2 rows containing the value 0
Thank you for your guidance

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KSSV
KSSV am 5 Okt. 2020
Bearbeitet: KSSV am 5 Okt. 2020
pop=randi([100],20,8);
[r1,c1]=size(pop);
pool = zeros([],c1) ;
count = 0 ;
for i=1:r1
A=randi(100);
if A<=90
count = count+1 ;
pool(count,:)=pop(i,:);
end
end
You need not to use loop...it can be vectorized.
pop=randi([100],20,8);
[r1,c1]=size(pop);
A = randi(100,1,r1) ;
pool = pop(A<=90,:) ;
  1 Kommentar
lech king
lech king am 5 Okt. 2020
Thank you very much
This is it

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