Pdepe: Spatial discretization has failed. Discretization supports only parabolic and elliptic equations, with flux term involving spatial derivative.

3 Ansichten (letzte 30 Tage)
Hi,
I was trying to solve PDEs system about diffusion on catalyst (modeled by deactivation model), which yields:
Error using pdepe (line 293)
Spatial discretization has failed. Discretization supports only parabolic
and elliptic equations, with flux term involving spatial derivative.
Error in Resolution (line 30)
sol = pdepe(m,@eqn2,@initial2,@bc2,x,t);
After read model in attchament, please see the code below:
global Def T Dp R cAO k kd kO cW alphaO gamma
%Parameters
T = 333; %[=]K
Dp = 2; %[=]m
Def = 10^-5; %
cAO = 0.0001; %[=]kmol/m^3 intial valure of concentration
cW = 0.0001;%[=]kmol/m^3
R = Dp/2;
k = (1.191*10^5)*exp(-7.544/(0.001607460438947*T));
kd = (4.299*10^3)*(exp(-6.86/(0.002102114315754*T)));
kO =k*cW;
gamma = 1;
alphaO = 1; %intial value of catalyst activity
%PDE2: MATLAB script M-file that solves the PDE
%stored in eqn2.m, bc2.m, and initial2.m
m = 2; %spheric
x = linspace(0,R,10);
t = linspace(0,1,10);
sol = pdepe(m,@eqn2,@initial2,@bc2,x,t);
u1 = sol(:,:,1);
u2 = sol(:,:,2);
%--------------------------------------------------------
%EQN2: MATLAB M-file that contains the coefficents for
%a system of two PDE in time and one space dimension.
function [c,b,s] = eqn2(x,t,u,DuDx)
global Def kO kd gamma
c = [1; 1];
b = [Def; 0] .* DuDx;
s = [- kO*u(1)*(u(2));-kd*u(1)*((u(2)).^(gamma+1))];
% --------------------------------------------------------
%INITIAL2: MATLAB function M-file that defines initial conditions
%for a system of two PDE in time and one space variable.
function value = initial2(x);
global cAO alphaO
value = [cAO; alphaO];
% --------------------------------------------------------
%BC2: MATLAB function M-file that defines boundary conditions
%for a system of two PDE in time and one space dimension.
function [pl,ql,pr,qr] = bc2(xl,ul,xr,ur,t)
global cAO R
pl = [0; 0];
ql = [1; 0];
pr = [ur(R)-cAO; 0];
qr = [0; 0];

Akzeptierte Antwort

Bill Greene
Bill Greene am 3 Okt. 2020
Bearbeitet: Bill Greene am 3 Okt. 2020
The boundary conditions for your second PDE are invalid. These should work:
pl = [0; 0];
ql = [1; 1];
pr = [ur(1)-cAO; 0];
qr = [0; 1];
  3 Kommentare
Bill Greene
Bill Greene am 3 Okt. 2020
Sorry, that is due to another error in your original script that I missed. I edited my answer to fix that.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by