Applying function to signal

I have an I-dimensional input signal
x(t)=[x1(t),...xI(t)]T
and J-dimensional input-output function
g(x)=[g1(x),....gJ(x)]T
these functions are saved as a J-dimensional matrix, while applying these functions to the input signal I should get the J-dimensional output signal by,
yj(t)=gj(x(t)) where j={1,2....J}
How to implement this in matlab?

Antworten (1)

Azzi Abdelmalek
Azzi Abdelmalek am 27 Jan. 2013
Bearbeitet: Azzi Abdelmalek am 27 Jan. 2013

0 Stimmen

function J=yourfunction(I)
%write your code
%J=...

6 Kommentare

Berbia
Berbia am 27 Jan. 2013
I mean both x(t) and g(x) are matrices with real values..what I have to do to get y(t)? for g(x(t)), is it enough to multiply both matrices?
Azzi Abdelmalek
Azzi Abdelmalek am 27 Jan. 2013
Can you provide an example?
Berbia
Berbia am 27 Jan. 2013
Bearbeitet: Berbia am 27 Jan. 2013
size(x)=[500 5], where t=5
size(g)=[200 5]
my output signal should be size(y)=[200 5]
its possible to change the size of g as required but the size x and y should be same..
Azzi Abdelmalek
Azzi Abdelmalek am 27 Jan. 2013
Bearbeitet: Azzi Abdelmalek am 27 Jan. 2013
I dont know what you mean by as required. Can you give a clear example with relation between inputs and outputs
Berbia
Berbia am 27 Jan. 2013
I'm trying to extract the slow features from the input signal by using the algorithm Slow Feature Analysis(SFA) by using the sfa-toolkit. I'm expecting the output should be 200*5, but the tool-kit returns the output signal of dimension 500*5, where 500 is the input signal dimension.
while I changing the Slow function dimension I met with the error
??? Error using ==> mtimes
Inner matrix dimensions must agree.
so I'm wondering the dimension of g(x) which should result me the output of dimension 200*5. Anyway I can manage my project, thank you for your time and consideration.
Azzi Abdelmalek
Azzi Abdelmalek am 27 Jan. 2013
Sorry, I can't understand.

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am 27 Jan. 2013

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