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Lotka Volterra with an additional parameter

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I have attempted to model the equations provided below. the code keeps giving me an error when I try to plot the figure using the parameter k instead of t. I am trying to model the effect of varying k on the population dynamics for both prey and predator.
note: if I use plot(k, P) it gives me a complicated and entirely different graph that is unreadable.
Script Window:
tspan = [0, 400];
P0 = [200, 50];
k = [-1, 1];
[t,P] = ode45(@(t,P)lotkavolterra(t,P),tspan,P0);
plot(k,P(:,1),k,P(:,2)) %This section gives me the error. It works, however, if I use t instead of k.
function [dPdt] = lotkawithk(t,P)
alpha = 1;
beta = 0.05;
gamma = 0.05;
delta = 0.0025;
x = P(1);
y = P(2);
dPdt = zeroes(2,1);
dPdt(1) = alpha*x - (beta*x*y)/((log(exp(1)+t))^k);
dPdt(2) = (delta*x*y)/((log(exp(1)+t))^k) - (gamma*y);
end

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Accepted Answer

Star Strider
Star Strider on 25 Sep 2020
I cannot imagine how you got that code to work at all, considering that the function you call in ode45 is not the function you posted!
Try this:
tspan = linspace(0, 400, 100);;
P0 = [200, 50];
k = [-1, 1];
for k1 = 1:numel(k)
[t,P] = ode45(@(t,P)lotkawithk(t,P,k(k1)),tspan,P0);
Pm{k1} = P;
end
figure
hold on
for k1 = 1:numel(k)
plot(t,Pm{k1}(:,1), t,Pm{k1}(:,2), 'DisplayName',sprintf('k = %d',k(k1))) %This section gives me the error. It works, however, if I use t instead of k.
end
grid
legend
function [dPdt] = lotkawithk(t,P,k)
alpha = 1;
beta = 0.05;
gamma = 0.05;
delta = 0.0025;
x = P(1);
y = P(2);
dPdt = zeros(2,1);
dPdt(1) = alpha*x - (beta*x*y)/((log(exp(1)+t))^k);
dPdt(2) = (delta*x*y)/((log(exp(1)+t))^k) - (gamma*y);
end
Note that ‘k’ is passed as a parameter.
Make appropriate changes to get different results.

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Star Strider
Star Strider on 25 Sep 2020
My pleasure!
It is possible. However plotting a (100x1) vector dependent variables against a scalar independent variable produces uninterpretable results, so it’s not worth the effort:
figure
hold on
for k1 = 1:numel(k)
plot(k(k1),Pm{k1}(:,1), '.', 'LineWidth',1.5, 'DisplayName',sprintf('Predator (k = %d)',k(k1))) %This section gives me the error. It works, however, if I use t instead of k.
plot(k(k1),Pm{k1}(:,2), '.', 'LineWidth',1.5, 'DisplayName',sprintf('Prey (k = %d)',k(k1)))
end
hold off
grid
xlim([-1.1 1.1])
legend('Location','N')
Note that this uses a marker to plot the points, because they are plotted as individual points, not lines. If you didn’t plot markers, that’s likely the reason that nothing showed up when you attempted to plot it.
Still another option is to plot them in 3D:
figure
hold on
for k1 = 1:numel(k)
plot3(k(k1)*ones(size(t)),t,Pm{k1}(:,1), 'LineWidth',1.5, 'DisplayName',sprintf('Predator (k = %d)',k(k1))) %This section gives me the error. It works, however, if I use t instead of k.
plot3(k(k1)*ones(size(t)),t,Pm{k1}(:,2), 'LineWidth',1.5, 'DisplayName',sprintf('Prey (k = %d)',k(k1)))
end
hold off
grid
xlim([-1.1 1.1])
legend('Location','NW')
view(30, 30)
Experiment with these to see what works best for you.
Khushi Patel
Khushi Patel on 25 Sep 2020
Oh okay. Greatly appreciate the help and the clarification about plotting k!

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