Converting Euler's method calculation into matlab
5 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Dai Nguyen
am 25 Sep. 2020
Kommentiert: Dai Nguyen
am 25 Sep. 2020
Hi I wanna use Matlab to solver for an Euler calculation with the range of t from 0 to 10 with 0.5 step. however for some reason my code isn't working. The initial y=0
this is the equation dy/dt=(3*Q/A*(sin(x))^2))-(alpha*(1+y)^1.5)/Q
% Euler's Method
% Initial conditions and setup
Q=400
A=1200
alph=160
h = 0.5; % step size
t = 0:0.5:10; % the range of t
y = zeros(size(t)); % allocate the result y
y(1) = 0; % the initial y value
n = numel(y); % the number of y values
% The loop to solve the DE
for i=1:n-1
f = (3*(Q/A)*(sin(t))^2)-((alph*(1+y(i))^1.5)/A)
y(i+1) = y(i) + h * f;
end
plot(x,y); grid on
0 Kommentare
Akzeptierte Antwort
Rafael Hernandez-Walls
am 25 Sep. 2020
tray this:
% Initial conditions and setup
Q=400;
A=1200;
alph=160;
h = 0.5; % step size
t = 0:0.5:10; % the range of t
y = zeros(size(t)); % allocate the result y
y(1) = 0; % the initial y value
n = numel(y); % the number of y values
% The loop to solve the DE
for i=1:n-1 % v---- t fot t(i)
f = (3*(Q/A)*(sin(t(i))).^2)-((alph*(1+y(i)).^1.5)/A);
y(i+1) = y(i) + h * f;
end
plot(t,y); grid on
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!