How to plot the values found in a for loop?

I have the following code
for g=((-3*pi())/2):0.1:0
Ebca=X*(Ex*cos((pi()/6)+g)^2+Ey*sin((pi()/6)+g)^2+Gamxy*sin((pi()/6)+g)*cos((pi()/6)+g))
Ebcb=Ex*cos(-(pi()/6)+g)^2+Ey*sin(-(pi()/6)+g)^2+Gamxy*sin(-(pi()/6)+g)*cos(-(pi()/6)+g);
Ebcc=Ex*cos((pi()/2)+g)^2+Ey*sin((pi()/2)+g)^2+Gamxy*sin((pi()/2)+g)*cos((pi()/2)+g);
end
I need to plot each Ebca, Ebcb, Ebcc value found in the loop with respect to g, how would i do this?
I know i need to create an array with the values found for each function with each value of g but I do no know how to do this.

Antworten (1)

David Hill
David Hill am 24 Sep. 2020

0 Stimmen

Are X, Ex, Ey, Gamxy constants not listed? Recommned executing without loop; otherwise you need to index Ebca/Ebcb/Ebcc. Currently you are overriding them during each loop execution.
g=-3*pi/2:0.1:0
Ebca=X*(Ex*cos((pi/6)+g).^2+Ey*sin((pi/6)+g).^2+Gamxy*sin((pi/6)+g).*cos((pi/6)+g));
Ebcb=Ex*cos(-(pi/6)+g).^2+Ey*sin(-(pi/6)+g).^2+Gamxy*sin(-(pi/6)+g).*cos(-(pi/6)+g);
Ebcc=Ex*cos((pi/2)+g).^2+Ey*sin((pi/2)+g).^2+Gamxy*sin((pi/2)+g).*cos((pi/2)+g);
plot(g,Ebca,g,Ebcb,g,Ebcc);

3 Kommentare

these constants were found in an earlier part of the code
Here is the full code to this part
%% Part E
for g=(pi()/3)
Eaa=Ex*cos((pi()/6)+g)^2+Ey*sin((pi()/6)+g)^2+Gamxy*sin((pi()/6)+g)*cos((pi()/6)+g);
Eab=Ex*cos(-(pi()/6)+g)^2+Ey*sin(-(pi()/6)+g)^2+Gamxy*sin(-(pi()/6)+g)*cos(-(pi()/6)+g);
Eac=Ex*cos((pi()/2)+g)^2+Ey*sin((pi()/2)+g)^2+Gamxy*sin((pi()/2)+g)*cos((pi()/2)+g);
end
for g=(-pi()/6)
Eba=Ex*cos((pi()/6)+g)^2+Ey*sin((pi()/6)+g)^2+Gamxy*sin((pi()/6)+g)*cos((pi()/6)+g);
Ebb=Ex*cos(-(pi()/6)+g)^2+Ey*sin(-(pi()/6)+g)^2+Gamxy*sin(-(pi()/6)+g)*cos(-(pi()/6)+g);
Ebc=Ex*cos((pi()/2)+g)^2+Ey*sin((pi()/2)+g)^2+Gamxy*sin((pi()/2)+g)*cos((pi()/2)+g);
end
for g=(pi()/2)
Eaba=Ex*cos((pi()/6)+g)^2+Ey*sin((pi()/6)+g)^2+Gamxy*sin((pi()/6)+g)*cos((pi()/6)+g);
Eabb=Ex*cos(-(pi()/6)+g)^2+Ey*sin(-(pi()/6)+g)^2+Gamxy*sin(-(pi()/6)+g)*cos(-(pi()/6)+g);
Eabc=Ex*cos((pi()/2)+g)^2+Ey*sin((pi()/2)+g)^2+Gamxy*sin((pi()/2)+g)*cos((pi()/2)+g);
end
g=((-3*pi())/2):0.1:0
Ebca=(Ex*cos((pi()/6)+g)^2+Ey*sin((pi()/6)+g)^2+Gamxy*sin((pi()/6)+g)*cos((pi()/6)+g));
Ebcb=Ex*cos(-(pi()/6)+g)^2+Ey*sin(-(pi()/6)+g)^2+Gamxy*sin(-(pi()/6)+g)*cos(-(pi()/6)+g);
Ebcc=Ex*cos((pi()/2)+g)^2+Ey*sin((pi()/2)+g)^2+Gamxy*sin((pi()/2)+g)*cos((pi()/2)+g);
Nick Kavouris
Nick Kavouris am 24 Sep. 2020
the code you provided me worked beautifully! thank you for the assistance
David Hill
David Hill am 24 Sep. 2020
If you get a change, please accept the answer to close the question.

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