Filter löschen
Filter löschen

Analysing Equation in matlab

1 Ansicht (letzte 30 Tage)
Shawaiz Akhter
Shawaiz Akhter am 24 Sep. 2020
I am new to matlab and I made a graph of flight score against payload to find apoint where we can get max flight score but i ended up getting blank graph.
This is a code I used. Thank you very much for your time.
nl = [1 , 2];
ns = [2 , 3];
payload = [300 , 400];
x = 1*nl;
y = 0.4*ns;
bonus = [0.5 + (1 *nl) + (0.4 * ns)];
T = [ 5 , 8];
d = payload .* bonus;
e = sqrt(d);
f = 80 * e;
fs = f/T;
plot(fs,payload)
  1 Kommentar
Johannes Hougaard
Johannes Hougaard am 24 Sep. 2020
I think this may well be one of the cases where it's kinda counterintuitive that / doesn't do what you think it does.
the '/' operator (mrdivide) is not identical to the './' operator (rdivide). I believe what you're looking for is the element-wise division (rdivide) and that your code should be
nl = [1 , 2];
ns = [2 , 3];
payload = [300 , 400];
x = 1*nl;
y = 0.4*ns;
bonus = [0.5 + (1 *nl) + (0.4 * ns)];
T = [ 5 , 8];
d = payload .* bonus;
e = sqrt(d);
f = 80 * e;
fs = f./T;
plot(fs,payload)

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Ollie A
Ollie A am 24 Sep. 2020
Be careful when multiplying and dividing arrays; you will need to use the dot notation.
You remembered it for
d = payload .* bonus;
but it is also needed when dividing
fs = f./T;
I also find it helpful to plot data points as crosses:
plot(xdata,ydata,'x')
hold on
plot(xdata,ydata)
that way if you only have 1 data point it will still appear on the plot as a cross.
Also note: if you want flight score on the y-axis and payload on the x-axis, it will be
plot(payload,fs)
  1 Kommentar
Johannes Hougaard
Johannes Hougaard am 24 Sep. 2020
if you like the 'line with cross notation' it's not necessary to call the hold on and a second call to plot you can simple do that by
plot(xdata,ydata,'-x');

Melden Sie sich an, um zu kommentieren.

Tags

Produkte


Version

R2016a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by