Counting changes binary number batch
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi If I have a binary data f.ex. (see data below) would it be possible to count how often it changes and say that we don't count it as a change if one number in a long run of number variates?
data = [ 0 1 1 1 1 1 0 0 1 0 0 0 1 1 1 1 1];
For this data we would say we don't count take data(1) but we count data(2:6) as a change. Then data(7:12) and that data(9) doesn't effect the count.
Is it possible to construct a general code for this?
0 Kommentare
Akzeptierte Antwort
Walter Roberson
am 16 Jan. 2013
t = data;
t(2:end-1) = t(2:end-1) | (t(1:end-2) & t(3:end));
numchange = sum( t(1:end-1) ~= t(2:end) );
2 Kommentare
Walter Roberson
am 16 Jan. 2013
The second line was intended to adjust for those cases, but I realize now it only adjusts for the case of a 0 in the middle of 1's.
Let's see...
t = data;
mask = (t(1:end-2) ~= t(2:end-1)) & (t(1:end-2) == t(3:end));
t([false mask false]) = ~t([false mask false]);
numchange = sum( t(1:end-1) ~= t(2:end) );
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Author Block Masks finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!