Taylor series: Error estimation

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Rahul Janardhanan
Rahul Janardhanan am 29 Aug. 2020
Kommentiert: David Hill am 30 Aug. 2020
Trying to estimate the error for taylor series expansion for 1/1-x. I'm trying to see the convergence for various values of N (no. of iterations) within a certain domain (x). I want to know how to calculate the error and plot it vs changing N.
This is what I have so far:
x= -0.9:0.05:0.9;
y= 1./(1-x);
N = 1; %N: no. of terms
y1 = 0*y;
for i = 0:N
y1= y1+(x.^i);
e1= abs(y-y1);
end
N2 = 2;
y2=0*y;
for i = 0:N2
y2 = y2+(x.^i);
e2= abs(y-y2);
end
N3 = 10;
y3=0*y;
for i= 0:N3
y3= y3+(x.^i);
e3= abs(y-y3);
end
N4 = 100;
y4=0*y;
e4 = 0*0;
for i = 0:N4
y4 = y4+(x.^i);
e4 = abs(y-y4);
end
hold on
plot(x,y,'*r')
plot(x,y1,'-b');
plot(x,y2,'^g');
plot(x,y3,'>k');
plot(x,y4,'--m');
hold off
figure
hold on
grid on
plot(1:N+1,e1,'ok'); %Matlab shows an error while doing this
plot(1:N2+1,e2,'-b');
plot(1:N3+1,e3,'^g');
plot(1:N4+1,e4,'pc');
hold off

Antworten (1)

David Hill
David Hill am 30 Aug. 2020
x= (-0.9:0.05:0.9)';
y= 1./(1-x);
m=cumsum(repmat(x,1,101).^(0:100),2);
err=abs(y-m);
surf(repmat(x,1,101),repmat([0:100],37,1),err);
figure;
hold on;
grid on;
plot(x,y,'*r');
plot(x,m(:,2),'-b');
plot(x,m(:,3),'^g');
plot(x,m(:,11),'>k');
plot(x,m(:,101),'--m');
  2 Kommentare
Rahul Janardhanan
Rahul Janardhanan am 30 Aug. 2020
Can you please elaborate about what the surf plot displays? Thanks!
David Hill
David Hill am 30 Aug. 2020
The surface plot is displaying all the x-values, N from 0-100, and corresponding errors on the z-axis.

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