Cell array summation when arrays are different sizes
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I am trying to some cell arrays containing matrices of different sizes stored at designated index points to arrays. See the below desired outputs.
% First Cell Input
cellname = {...
[1 1 1; ...
2 2 2; ...
3 3 3], ...
[1 1 1; ...
2 2 2; ...
3 3 3; ...
4 4 4; ...
5 5 5; ...
6 6 6], ...
[1 1 1; ...
2 2 2; ...
3 3 3; ...
4 4 4; ...
5 5 5; ...
6 6 6; ...
7 7 7; ...
8 8 8; ...
9 9 9]};
% Summed rowise to the below matrix
output1 =[9
18
27
16
30
36
21
24
27]
output1b =[3 3 3; ...
6 6 6; ...
9 9 9; ...
8 8 8; ...
10 10 10; ...
12 12 12; ...
7 7 7; ...
8 8 8; ...
9 9 9]
% Second Cell Input
cellname2 = {...
[1 2 3; ...
1 2 3; ...
1 2 3], ...
[1 2 3 4 5 6; ...
1 2 3 4 5 6; ...
1 2 3 4 5 6], ...
[1 2 3 4 5 6 7 8 9; ...
1 2 3 4 5 6 7 8 9; ...
1 2 3 4 5 6 7 8 9]};
% Summed columnwise to the below matrix
output2 = [9 18 27 24 30 36 21 24 27]
output2b = [3 6 9 8 10 12 7 8 9; ...
3 6 9 8 10 12 7 8 9; ...
3 6 9 8 10 12 7 8 9]
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Bruno Luong
am 26 Aug. 2020
Bearbeitet: Bruno Luong
am 26 Aug. 2020
I do just one, let you adapt to the second.
cellname = {...
[1 1 1; ...
2 2 2; ...
3 3 3], ...
[1 1 1; ...
2 2 2; ...
3 3 3; ...
4 4 4; ...
5 5 5; ...
6 6 6], ...
[1 1 1; ...
2 2 2; ...
3 3 3; ...
4 4 4; ...
5 5 5; ...
6 6 6; ...
7 7 7; ...
8 8 8; ...
9 9 9]};
s1 = cellfun('size',cellname,1)
n = max(s1);
Ap = cellfun(@(a) [a;zeros(n-size(a,1),size(a,2))], cellname, 'unif', 0);
output1 = sum(cell2mat(Ap),2)
output1b = sum(cat(3,Ap{:}),3) % NOTE output1 is sum(output1b,2)
1 Kommentar
Mau
am 26 Aug. 2020
KALYAN ACHARJYA
am 26 Aug. 2020
"I am trying to some cell arrays containing matrices of different sizes stored at designated index points to arrays. See the below desired outputs"
Option 1: If you are looking for sum of all array elments within the cell array
data=cell2mat(result(cell_array));
result=sum(data(:))
Option 2: If you are looking for sum of invividial elments (single matrix) within the cell array
result=zeros(1,length(cell_array))
for i=1:length(cell_array)
temp=cell_array{i};
result(i)=sum(temp(:));
end
result
You may avoid the loop also here
1 Kommentar
Mau
am 26 Aug. 2020
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