Recursion in matrix calculation

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StillANovice on 25 Aug 2020
Edited: James Tursa on 25 Aug 2020
How does recursion work in this context, as in how did the function CalDet manage to calculate the determinant of the minor without explicitly writing an equation?
function [determinant] = CalDet(M)
dimensionM = size(M);
if (dimensionM(1) == 1)
determinant = M(1, 1);
determinant = 0;
for i = 1:dimensionM(2)
determinant = determinant + (-1)^(i+1) * M(1, i) * CalDet(MMin(M, 1, i));
function [MatrixMinor] = MMin(M, i, j)
dimensionM = size(M);
MatrixMinor = M([1:(i-1) (i+1):dimensionM(1)], [1:(j-1) (j+1):dimensionM(2)]);

Answers (1)

James Tursa
James Tursa on 25 Aug 2020
Edited: James Tursa on 25 Aug 2020
This uses recursive calls (CalDet calls CalDet with smaller matrices until the size is 1x1). I.e., the recursion continues all the way down until the input is a 1x1 matrix, at which point the result is simply M(1,1) and then the results get passed back up through the stack of calls.
See Laplace's expansion and the adjugate matrix here:
BTW, this is not a good numerical technique.


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