Solve numerical equation with Y at both sides

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Ron Nativ
Ron Nativ am 23 Aug. 2020
Kommentiert: Star Strider am 24 Aug. 2020
Hi all,
I have a general equation I would like to solve. However, it contains the dependent variable Y on both sides.
The eqaution is: Y/Y_0 = B * (1 + x*Y/D)^0.5 * (1-x)^alpha
Where x is the independent variable,
and Y_0, B, D and alpha are constants. What would be the most appropriate function in Matlab for this particular problem?
Thanks,
Ron

Antworten (3)

KSSV
KSSV am 23 Aug. 2020
You can use symbolic package. Something like this:
syms Y_0 Y B x Y D alpha
eqn = Y/Y_0 - B * (1 + x*Y/D)^0.5 * (1-x)^alpha==0 ;
s = solve(eqn,Y)
  1 Kommentar
Ron Nativ
Ron Nativ am 24 Aug. 2020
Thank you KSSV. Is there a big difference between this and using vpasolve?

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Star Strider
Star Strider am 23 Aug. 2020
A numeric approach:
Y_0 = 3; % Define Constants
B = 5;
D = 7;
alpha = 11;
x = linspace(0, 0.9, 10);
Yfcn = @(Y,x) B * sqrt(1 + x*Y/D) .* (1-x).^alpha - Y/Y_0; % Use Element-Wise Operations
for k = 1:numel(x)
Y(k) = fzero(@(Y)Yfcn(Y,x(k)), 0.1);
end
figure
plot(x, Y)
grid
Note that if ‘x>1’ the result will be complex (regardless of what the other constants are), and the fzero function will fail. Consider using fsolve instead in this event.
  2 Kommentare
Ron Nativ
Ron Nativ am 24 Aug. 2020
Thanks Star Strider. Luckiliy, my x values are always between 0 and 1.
Star Strider
Star Strider am 24 Aug. 2020
Then this should work!

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Alan Stevens
Alan Stevens am 23 Aug. 2020
Bearbeitet: Alan Stevens am 23 Aug. 2020
Your equation can also be expressed as a quadratic in Y
which could be solved using roots (for specified values of x).
You would need to check that the solutions were consistent with the original equation.

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