How to calculate max multiplication possibility of three adjacent numbers in 10*10 matrix?
5 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Asrorkhuja Ortikov
am 17 Aug. 2020
Kommentiert: Asrorkhuja Ortikov
am 17 Aug. 2020
I have a matrix of 10 to 10 size of random digits from 0 to 9. How to calculate possible max multiplication of three adjacent numbers in matrix? I would like to consider only vertical and horizontal adjacent numbers, not diagonal.
r = randi([0 9],10,10);
0 Kommentare
Akzeptierte Antwort
Bruno Luong
am 17 Aug. 2020
% Test matrix
A=randi([0 9],10,10)
B=cat(3,movprod(A,3,1),movprod(A,3,2));
[maxB,imax]=max(B,[],'all','linear');
[i,j,k]=ind2sub(size(B),imax);
if k==1
i=max(i-1,1):min(i+1,size(A,1));
j=j+zeros(size(i));
else
j=max(j-1,1):min(j+1,size(A,2));
i=i+zeros(size(j));
end
ilin = sub2ind(size(B),i,j);
% Display the adjadcent elements
fm1 = repmat('A(%d,%d)*', 1, length(i));
fm1(end) = [];
fm2 = repmat('%d*', 1, length(i));
fm2(end) = [];
fprintf(['%d = ' fm1 ' = ' fm2, '\n'], maxB, [i(:) j(:)]', A(ilin));
3 Kommentare
Bruno Luong
am 17 Aug. 2020
The size of the array is in the first line
A=randi([0 9],10,10)
The length of the adjacent elements are in the second arguments of MOVPROD in the second statement
B=cat(3,movprod(A,3,1),movprod(A,3,2));
Weitere Antworten (1)
Walter Roberson
am 17 Aug. 2020
conv2(A, ones(1,n), 'same')
and same with ones(n, 1)
take max() over all of it.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Resizing and Reshaping Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!