Force tiledlayout('flow') to layout vertically
77 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
The problem I have with tiledlayout('flow') is that it it will often end up arranging the plots in a 2x2 grid, rather than a 4x1.
I understand tiledlayout('flow') tries to keep a 4:3 ratio for plots, but this is not useful for my data.
Tiledlayout(x,1) won't work because I don't know x beforehand.
I had hoped that in the case of tiledlayout(x,1) I could set the GridSize property, but it is read only.
Any suggestions on how to overcome this would be helpful, thank you.
0 Kommentare
Akzeptierte Antwort
Dave B
am 17 Mär. 2023
Starting in R2023a you can use the 'horizontal' and 'vertical' tile arrangements to accomplish layouts that are dynamically sized but only in one direction. More information available in the tiledlayout documentation.
figure(1)
t=tiledlayout('horizontal');
nexttile
plot(rand(1,10))
nexttile
bar(rand(1,10))
nexttile
scatter(rand(1,10),rand(1,10))
figure(2)
t=tiledlayout('vertical');
nexttile
plot(rand(1,10))
nexttile
bar(rand(1,10))
nexttile
scatter(rand(1,10),rand(1,10))
0 Kommentare
Weitere Antworten (1)
Srivardhan Gadila
am 20 Aug. 2020
Based on the above information and the documentation of tiledlayout & nexttile, for this particular problem you can make use of the 'nexttile(span)' syntax as follows:
% Let the max number tiles are maxTiles = 1000 (>>n or just >=n)
maxTiles = 1000;
x = linspace(0,30);
tiledlayout('flow')
n = randi([1 10]);
for i=1:n
nexttile([1 maxTiles])
y = rand(1,numel(x));
plot(x,y)
end
Siehe auch
Kategorien
Mehr zu Annotations finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!